如何通过单击删除按钮重置整个视图
How to reset the whole View by clicking the delete Button
我制作了一个自定义视图,其中包含一个 ImageView、一个 TextView 和一个删除按钮。
我想在单击与其关联的删除按钮时重置特定视图。
请告诉如何实现这个。
这是我的 MainActivity.java
package com.khurana.nikhil.list1;
import android.support.v7.app.ActionBarActivity;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.AdapterView;
import android.widget.ArrayAdapter;
import android.widget.LinearLayout;
import android.widget.ListView;
import android.widget.TextView;
import android.widget.Toast;
public class MainActivity extends ActionBarActivity {
ListView lv;
TextView tv1, tv2;
View v1;
public String[] s = {"nikhil", "mukul", "kunal"};
public int[] img = {R.drawable.rty, R.drawable.sf, R.drawable.rty};
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ListView lv = (ListView) findViewById(R.id.listView);
CustomAdapter cad = new CustomAdapter(MainActivity.this, s, img);
lv.setAdapter(cad);
lv.setOnItemClickListener(new AdapterView.OnItemClickListener()
{
public void onItemClick(AdapterView<?> parent,View v,int position,long id)
{
Toast.makeText(MainActivity.this,"You clicked "+s[position],Toast.LENGTH_SHORT).show();
}
});
}
}
这里是CustomAdapter.java
package com.khurana.nikhil.list1;
import android.content.Context;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.Button;
import android.widget.ImageView;
import android.widget.TextView;
public class CustomAdapter extends ArrayAdapter<String>{
Context c1;
String s1[];
int s2[];
CustomAdapter(Context c,String s[],int s3[])
{
super(c,R.layout.tcustom,s);
this.c1=c;
this.s1=s;
this.s2=s3;
}
public View getView(int position,View v,ViewGroup parent)
{
LayoutInflater li=(LayoutInflater) c1.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
v=li.inflate(R.layout.tcustom,null);
TextView tv=(TextView)v.findViewById(R.id.textView);
ImageView im=(ImageView)v.findViewById(R.id.imageview);
tv.setText(s1[position]);
im.setImageResource(s2[position]);
Button bt=(Button)v.findViewById(R.id.button);
return v;
}
}
如果您希望视图消失:
yourView.setVisibility(View.GONE);
编辑:获取按钮的父视图:Android: Making changes to a button's parent view
((LinearLayout)yourView.getParent()).removeView(yourView);
或者直接从布局调用
yourRelativeLayout.removeView(yourView)
视图对 GONE 的可见性也不会从内存中删除您的视图。请具体一点,你想保留你的观点以备将来使用吗?
我建议在您的适配器 class 中使用 ArrayList 而不是 String[]。它使删除或编辑视图及其背后的关联数据变得容易得多。我使用 this post 将您的 String[] 转换为 ArrayList,删除项目并转换回 String[]。
这应该在按钮点击时起作用:
在您的适配器中 class:
public View getView(int position,View v,ViewGroup parent)
{
LayoutInflater li=(LayoutInflater) c1.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
v=li.inflate(R.layout.tcustom,null);
TextView tv=(TextView)v.findViewById(R.id.textView);
ImageView im=(ImageView)v.findViewById(R.id.imageview);
tv.setText(s1[position]);
im.setImageResource(s2[position]);
Button bt=(Button)v.findViewById(R.id.button);
bt.setTag(position); //important so we know which item to delete on button click
bt.setOnClickListener(new View.OnClickListener() {
public void onClick(View v)
{
int positionToRemove = v.getTag(); //get the position of the view to delete stored in the tag
removeItem(positionToRemove); //remove the item
}
});
return v;
}
public void removeItem(int position){
//convert array to ArrayList, delete item and convert back to array
ArrayList<String> a = new ArrayList<>(Arrays.asList(s1));
a.remove(i);
strings = new String[a.size()];
s1= a.toArray(strings);
notifyDataSetChanged(); //refresh your listview based on new data
}
@Override
public int getCount() {
return s1.length;
}
@Override
public String getItem(int position) {
return s1[position];
}
如果您在列表视图中工作,您应该调用 notifyDataSetChanged()
适配器。你的 getView() 方法可以是这样的:
按钮上的动作可以是这样的
Button bt=(Button)v.findViewById(R.id.button);
bt.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
s1 = ArrayUtils.remove(s1, position);
s2 = ArrayUtils.remove(s2, position);
notifyDataSetChanged();
}
});
我制作了一个自定义视图,其中包含一个 ImageView、一个 TextView 和一个删除按钮。
我想在单击与其关联的删除按钮时重置特定视图。
请告诉如何实现这个。
这是我的 MainActivity.java
package com.khurana.nikhil.list1;
import android.support.v7.app.ActionBarActivity;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.AdapterView;
import android.widget.ArrayAdapter;
import android.widget.LinearLayout;
import android.widget.ListView;
import android.widget.TextView;
import android.widget.Toast;
public class MainActivity extends ActionBarActivity {
ListView lv;
TextView tv1, tv2;
View v1;
public String[] s = {"nikhil", "mukul", "kunal"};
public int[] img = {R.drawable.rty, R.drawable.sf, R.drawable.rty};
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ListView lv = (ListView) findViewById(R.id.listView);
CustomAdapter cad = new CustomAdapter(MainActivity.this, s, img);
lv.setAdapter(cad);
lv.setOnItemClickListener(new AdapterView.OnItemClickListener()
{
public void onItemClick(AdapterView<?> parent,View v,int position,long id)
{
Toast.makeText(MainActivity.this,"You clicked "+s[position],Toast.LENGTH_SHORT).show();
}
});
}
}
这里是CustomAdapter.java
package com.khurana.nikhil.list1;
import android.content.Context;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.Button;
import android.widget.ImageView;
import android.widget.TextView;
public class CustomAdapter extends ArrayAdapter<String>{
Context c1;
String s1[];
int s2[];
CustomAdapter(Context c,String s[],int s3[])
{
super(c,R.layout.tcustom,s);
this.c1=c;
this.s1=s;
this.s2=s3;
}
public View getView(int position,View v,ViewGroup parent)
{
LayoutInflater li=(LayoutInflater) c1.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
v=li.inflate(R.layout.tcustom,null);
TextView tv=(TextView)v.findViewById(R.id.textView);
ImageView im=(ImageView)v.findViewById(R.id.imageview);
tv.setText(s1[position]);
im.setImageResource(s2[position]);
Button bt=(Button)v.findViewById(R.id.button);
return v;
}
}
如果您希望视图消失:
yourView.setVisibility(View.GONE);
编辑:获取按钮的父视图:Android: Making changes to a button's parent view
((LinearLayout)yourView.getParent()).removeView(yourView);
或者直接从布局调用
yourRelativeLayout.removeView(yourView)
视图对 GONE 的可见性也不会从内存中删除您的视图。请具体一点,你想保留你的观点以备将来使用吗?
我建议在您的适配器 class 中使用 ArrayList 而不是 String[]。它使删除或编辑视图及其背后的关联数据变得容易得多。我使用 this post 将您的 String[] 转换为 ArrayList,删除项目并转换回 String[]。
这应该在按钮点击时起作用:
在您的适配器中 class:
public View getView(int position,View v,ViewGroup parent)
{
LayoutInflater li=(LayoutInflater) c1.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
v=li.inflate(R.layout.tcustom,null);
TextView tv=(TextView)v.findViewById(R.id.textView);
ImageView im=(ImageView)v.findViewById(R.id.imageview);
tv.setText(s1[position]);
im.setImageResource(s2[position]);
Button bt=(Button)v.findViewById(R.id.button);
bt.setTag(position); //important so we know which item to delete on button click
bt.setOnClickListener(new View.OnClickListener() {
public void onClick(View v)
{
int positionToRemove = v.getTag(); //get the position of the view to delete stored in the tag
removeItem(positionToRemove); //remove the item
}
});
return v;
}
public void removeItem(int position){
//convert array to ArrayList, delete item and convert back to array
ArrayList<String> a = new ArrayList<>(Arrays.asList(s1));
a.remove(i);
strings = new String[a.size()];
s1= a.toArray(strings);
notifyDataSetChanged(); //refresh your listview based on new data
}
@Override
public int getCount() {
return s1.length;
}
@Override
public String getItem(int position) {
return s1[position];
}
如果您在列表视图中工作,您应该调用 notifyDataSetChanged()
适配器。你的 getView() 方法可以是这样的:
按钮上的动作可以是这样的
Button bt=(Button)v.findViewById(R.id.button);
bt.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
s1 = ArrayUtils.remove(s1, position);
s2 = ArrayUtils.remove(s2, position);
notifyDataSetChanged();
}
});