根据其他列表选择的值更新下拉列表中的选择值

Question

我正在尝试弄清楚如何使用 Vanilla JS 在几个下拉列表中动态选择值。我有 3 个具有相同值的下拉列表。他们每个人都应该同时选择不同的值（不允许重复）。因此，一旦用户更改了一个列表中的另一个值，另一个列表的值也应相应更新。基本上，在这种情况下我需要交换他们的号码。但是我无法完成这项任务，因为我对 JS 和整体编程都很陌生。我试过以下：

// defining initial values
var startPoint = document.querySelectorAll("select");

// function to recalculate value of each list on change
function calculateNewValues() {
  var changes = new Array();
  // getting updated values from lists as an array
  var updatedValues = document.querySelectorAll("select");
  // looping through array
  for (let i = 0; i < updatedValues.length; i++) {
    // if in updated array value of current index isn't equal to value
    // of index in initial array
    if (updatedValues[i].value != startPoint[i].value) {
      // creating variable changes for tracking
      changes[i] = updatedValues[i].value;
    }
    // if var changes has been defined (i.e. value of any list was updated)
    if (changes.length > 0) {
      // finding index of initial array with same value
      var key = startPoint.findIndex(changes[i]);
      // setting value of found index to previously stored value in updated list
      updatedValues[key].value = startPoint[i].value;
    }
  }

  updatedValues.forEach(element => {
    console.log(element.value);
  });
}
// event listeners for change of every dropdown list
const lists = document.querySelectorAll("select");
for (k = 0; k < lists.length; k++) {
  lists[k].addEventListener("change", calculateNewValues, false);
}

<p>
  <select name="list1" id="list1">
    <option value="1" id="list1option1" selected>1</option>
    <option value="2" id="list1option2">2</option>
    <option value="3" id="list1option3">3</option>
  </select>
</p>
<p>
  <select name="list2" id="list2">
    <option value="1" id="list2option1">1</option>
    <option value="2" id="list2option2" selected>2</option>
    <option value="3" id="list2option3">3</option>
  </select>
</p>
<p>
  <select name="list3" id="list3">
    <option value="1" id="list3option1">1</option>
    <option value="2" id="list3option2">2</option>
    <option value="3" id="list3option3" selected>3</option>
  </select>
</p>

关于 if (changes.length > 0) { 我可能犯了一些错误但我不明白如何让这部分变得更好。

非常感谢。

Answer 1

您已将 startPoint 分配给 querySelectorAll。每当您编写相同的 querySelectorAll 时，它将保存完全相同的对象。因此，在您的情况下，startPoint 和 updatedValues 将始终相同。

我已将 startPoint 定义为值数组并将其值设置在 setStartingPointValues() 中。
已添加 target 作为正在更新的当前列表。
更新了 if (target.id == updatedValues[i].id && updatedValues[i].value != startPoint[i]) 并检索了 target 的旧值。
var key = startPoint.findIndex(x => x == target.value); 会发现 select 的值与新值相似。如果我们找到 key != -1，则将 select 更新为 oldValue.
在更改事件结束时调用 setStartingPointValues()。

// defining initial values
var startPoint = [];

// store values for all select.
function setStartingPointValues() {
  startPoint = [];
  document.querySelectorAll("select").forEach(x => startPoint.push(x.value));
}

setStartingPointValues();

// function to recalculate value of each list on change
function calculateNewValues() {
  let target = this;
  let oldValue = 0;
  // getting updated values from lists as an array
  var updatedValues = document.querySelectorAll("select");
  // looping through array
  for (let i = 0; i < updatedValues.length; i++) {
    // if in updated array value of current index isn't equal to value    
    // of index in initial array    
    if (target.id == updatedValues[i].id && updatedValues[i].value != startPoint[i]) {
      // creating variable changes for tracking
      // changes[i] = updatedValues[i].value;
      oldValue = startPoint[i];
    }
    // if var changes has been defined (i.e. value of any list was updated)

    // finding index of initial array with same value
    var key = startPoint.findIndex(x => x == target.value);
    // setting value of found index to previously stored value in updated list
    if (key !== -1)
      updatedValues[key].value = oldValue;

  }

  setStartingPointValues();
}
// event listeners for change of every dropdown list
const lists = document.querySelectorAll("select");
for (k = 0; k < lists.length; k++) {
  lists[k].addEventListener("change", calculateNewValues, false);
}

<p>
  <select name="list1" id="list1">
    <option value="1" id="list1option1" selected>1</option>
    <option value="2" id="list1option2">2</option>
    <option value="3" id="list1option3">3</option>
  </select>
</p>
<p>
  <select name="list2" id="list2">
    <option value="1" id="list2option1">1</option>
    <option value="2" id="list2option2" selected>2</option>
    <option value="3" id="list2option3">3</option>
  </select>
</p>
<p>
  <select name="list3" id="list3">
    <option value="1" id="list3option1">1</option>
    <option value="2" id="list3option2">2</option>
    <option value="3" id="list3option3" selected>3</option>
  </select>
</p>

Answer 2

定义良好的结构（在某处存储选定的值），其余的应该很容易

const lists = Array.from(document.querySelectorAll("#list")).map(element => {
  const options = Array.from(element.children);
  const selected = options.findIndex(child => child.selected) + 1;
  
  return {
    element,
    options,
    selected
  }
  
});

const calculateNewValues = ({target}) => {
  const value = Number(target.value);
  
  const currentList = lists.find(pr => pr.element === target);
  const list = lists.find(pr => pr.selected === value)
  const oldValue = currentList.selected;
  currentList.selected = value;

  list.options[value - 1].selected = false;
  list.options[oldValue - 1].selected = true;
  list.selected = oldValue;
  
}

for(let {element} of lists) {
  element.addEventListener("change", calculateNewValues, false);
}

<p>
    <select name="list1" id="list">
      <option value="1" selected>1</option>
      <option value="2">2</option>
      <option value="3">3</option>
    </select>
</p>
<p>
    <select name="list2" id="list">
      <option value="1">1</option>
      <option value="2" selected>2</option>
      <option value="3">3</option>
    </select>
</p>
<p>
    <select name="list3" id="list">
      <option value="1">1</option>
      <option value="2">2</option>
      <option value="3" selected>3</option>
    </select>
</p>

根据其他列表选择的值更新下拉列表中的选择值

Update selected value in dropdown list depending on other lists selected values

javascript

dropdown