将 gsub 用于 R 中字符串中的特定事件?
Using gsub for a specific occurrence in a string in R?
我有两个字符串:
mystring1 <- c("hello i am a cat. just kidding, i'm not a cat i'm a cat. dogs are the best animal. not cats!")
mystring2 <- c("hello i am a cat. just kidding, i'm not a cat i'm a cat. but i have a cat friend that is a cat.")
我想将两个字符串中第三次出现的单词 cat 更改为 dog。
理想情况下,string1
和 string2
应该是:
mystring1
[1] "hello i am a cat. just kidding, i'm not a cat i'm a dog. dogs are the best animal. not cats!"
mystring2
[1] "hello i am a cat. just kidding, i'm not a cat i'm a dog. but i have a cat friend that is a cat."
最好的方法是什么?到目前为止,我只使用 gsub
来替换字符,但我不知道这是否可以用来替换特定出现的字符。
你可以使用
mystring1 <- c("hello i am a cat. just kidding, i'm not a cat i'm a cat. dogs are the best animal. not cats!")
mystring2 <- c("hello i am a cat. just kidding, i'm not a cat i'm a cat. but i have a cat friend that is a cat who knows a cat knowing a cat.")
sub("((cat.*?){2})\bcat\b", "\1dog", mystring1, perl=TRUE)
这给出了
> sub("((cat.*?){2})\bcat\b", "\1dog", c(mystring1, mystring2), perl=TRUE)
[1] "hello i am a cat. just kidding, i'm not a cat i'm a dog. dogs are the best animal. not cats!"
[2] "hello i am a cat. just kidding, i'm not a cat i'm a dog. but i have a cat friend that is a cat who knows a cat knowing a cat."
您可以使用gsubfn
library(gsubfn)
p <- proto(fun = function(this, x) if(count == 3) 'dog' else x)
gsubfn('cat', p, c(mystring1, mystring2))
# [1] "hello i am a cat. just kidding, i'm not a cat i'm a dog. dogs are the best animal. not cats!"
# [2] "hello i am a cat. just kidding, i'm not a cat i'm a dog. but i have a cat friend that is a cat."
或者,如果它需要被单词边界包围,
gsubfn('\bcat\b', p, c(mystring1, mystring2), perl = TRUE)
# [1] "hello i am a cat. just kidding, i'm not a cat i'm a dog. dogs are the best animal. not cats!"
# [2] "hello i am a cat. just kidding, i'm not a cat i'm a dog. but i have a cat friend that is a cat."
我有两个字符串:
mystring1 <- c("hello i am a cat. just kidding, i'm not a cat i'm a cat. dogs are the best animal. not cats!")
mystring2 <- c("hello i am a cat. just kidding, i'm not a cat i'm a cat. but i have a cat friend that is a cat.")
我想将两个字符串中第三次出现的单词 cat 更改为 dog。
理想情况下,string1
和 string2
应该是:
mystring1
[1] "hello i am a cat. just kidding, i'm not a cat i'm a dog. dogs are the best animal. not cats!"
mystring2
[1] "hello i am a cat. just kidding, i'm not a cat i'm a dog. but i have a cat friend that is a cat."
最好的方法是什么?到目前为止,我只使用 gsub
来替换字符,但我不知道这是否可以用来替换特定出现的字符。
你可以使用
mystring1 <- c("hello i am a cat. just kidding, i'm not a cat i'm a cat. dogs are the best animal. not cats!")
mystring2 <- c("hello i am a cat. just kidding, i'm not a cat i'm a cat. but i have a cat friend that is a cat who knows a cat knowing a cat.")
sub("((cat.*?){2})\bcat\b", "\1dog", mystring1, perl=TRUE)
这给出了
> sub("((cat.*?){2})\bcat\b", "\1dog", c(mystring1, mystring2), perl=TRUE)
[1] "hello i am a cat. just kidding, i'm not a cat i'm a dog. dogs are the best animal. not cats!"
[2] "hello i am a cat. just kidding, i'm not a cat i'm a dog. but i have a cat friend that is a cat who knows a cat knowing a cat."
您可以使用gsubfn
library(gsubfn)
p <- proto(fun = function(this, x) if(count == 3) 'dog' else x)
gsubfn('cat', p, c(mystring1, mystring2))
# [1] "hello i am a cat. just kidding, i'm not a cat i'm a dog. dogs are the best animal. not cats!"
# [2] "hello i am a cat. just kidding, i'm not a cat i'm a dog. but i have a cat friend that is a cat."
或者,如果它需要被单词边界包围,
gsubfn('\bcat\b', p, c(mystring1, mystring2), perl = TRUE)
# [1] "hello i am a cat. just kidding, i'm not a cat i'm a dog. dogs are the best animal. not cats!"
# [2] "hello i am a cat. just kidding, i'm not a cat i'm a dog. but i have a cat friend that is a cat."