列出给定模型铁路上可能的火车路线
List possible train routes on a given model railway
我想计算给定模型铁路上的可用路线。
假设:
- 所有火车仅在称为火车站的定义点开始和停止。
- 火车在旅途中不会相撞。不用担心。
- 我们不必考虑火车的长度。我们假设它是一个火车头,它需要一个原子的space。
- 一个火车站只能停一列火车。
- 火车可以在同一个火车站起停。
所有火车的起始位置和结束位置都存储在地图中。所有排列都存储在一个列表中。示例:
iex(1)> Trains.list_routes(["ICE"], ["Hamburg", "Frankfurt"])
[
%{end: %{"ICE" => "Hamburg"}, start: %{"ICE" => "Hamburg"}},
%{end: %{"ICE" => "Frankfurt"}, start: %{"ICE" => "Frankfurt"}},
%{end: %{"ICE" => "Frankfurt"}, start: %{"ICE" => "Hamburg"}},
%{end: %{"ICE" => "Hamburg"}, start: %{"ICE" => "Frankfurt"}}
]
铁路模型可能如下所示(红色数字表示火车站):
对于该模型铁路上的两列火车,函数将以这种方式调用:
Trains.list_routes([:red_train, :blue_train], ["1", "2", "3", "4", "5"])
这是我当前的代码:
defmodule Trains do
@moduledoc """
Documentation for `Trains`.
"""
@doc """
Returns a list of all possible routes.
## Examples
iex> Trains.list_routes([:red_train, :blue_train], ["Station 1", "Station 2"])
[
%{
end: %{blue_train: "Station 2", red_train: "Station 1"},
start: %{blue_train: "Station 2", red_train: "Station 1"}
},
%{
end: %{blue_train: "Station 1", red_train: "Station 2"},
start: %{blue_train: "Station 1", red_train: "Station 2"}
},
%{
end: %{blue_train: "Station 1", red_train: "Station 2"},
start: %{blue_train: "Station 2", red_train: "Station 1"}
},
%{
end: %{blue_train: "Station 2", red_train: "Station 1"},
start: %{blue_train: "Station 1", red_train: "Station 2"}
}
]
"""
def list_routes([], []) do
[]
end
def list_routes([train], [station]) do
[
%{start: %{train => station}, end: %{train => station}}
]
end
def list_routes([train], [station1, station2]) do
[
%{start: %{train => station1}, end: %{train => station1}},
%{start: %{train => station2}, end: %{train => station2}},
%{start: %{train => station1}, end: %{train => station2}},
%{start: %{train => station2}, end: %{train => station1}}
]
end
def list_routes([train1, train2], [station1, station2]) do
[
%{
start: %{train1 => station1, train2 => station2},
end: %{train1 => station1, train2 => station2}
},
%{
start: %{train1 => station2, train2 => station1},
end: %{train1 => station2, train2 => station1}
},
%{
start: %{train1 => station1, train2 => station2},
end: %{train1 => station2, train2 => station1}
},
%{
start: %{train1 => station2, train2 => station1},
end: %{train1 => station1, train2 => station2}
}
]
end
def list_routes(trains, train_stations) do
# ???
end
end
当trains
的个数和train_stations
的个数都大于1时,如何遍历list_routes(trains, train_stations)
的所有组合?
根据您发布的代码,不清楚为什么一列火车允许相同的起点和终点站 %{start: %{train => station1}, end: %{train => station1}}
但两列火车不允许。
良好的开端应该是这样的:
iex|1 ▶ {trains, stations} =
{~w|red_train blue_train|a, ~w|1 2|}
#⇒ {[:red_train, :blue_train], ["1", "2"]}
iex|2 ▶ (for t1 <- trains, t2<- trains, t1 != t2,
s1 <- stations, s2 <- stations,
do: Enum.sort([{t1, s1}, {t2, s2}])
) |> Enum.uniq()
#⇒ [
# [blue_train: "1", red_train: "1"],
# [blue_train: "2", red_train: "1"],
# [blue_train: "1", red_train: "2"],
# [blue_train: "2", red_train: "2"]
# ]
无论如何,Kernel.SpecialForms.for/1
comprehension is your best friend here. Whether you need combinations and/or permutations, you might want to take a look at my Formulae
library, specifically at Formulae.Combinators
。
这是问题的解决方案。它使用 Formulae.
mix.exs
def deps do
[{:formulae, "~> 0.8"}]
end
lib/trains.ex
def list_routes([], []) do
[]
end
def list_routes(trains, train_stations)
when is_list(trains) and
is_list(train_stations) and
length(train_stations) >= length(trains) do
possible_states =
Enum.map(Formulae.permutations(train_stations, length(trains)), &Enum.zip(trains, &1))
for state_start <- possible_states, state_end <- possible_states do
%{start: state_start, end: state_end}
end
end
结果:
iex(1)> Trains.list_routes([:red_train, :blue_train], ["Station 1", "Station 2"])
[
%{
end: [red_train: "Station 1", blue_train: "Station 2"],
start: [red_train: "Station 1", blue_train: "Station 2"]
},
%{
end: [red_train: "Station 2", blue_train: "Station 1"],
start: [red_train: "Station 1", blue_train: "Station 2"]
},
%{
end: [red_train: "Station 1", blue_train: "Station 2"],
start: [red_train: "Station 2", blue_train: "Station 1"]
},
%{
end: [red_train: "Station 2", blue_train: "Station 1"],
start: [red_train: "Station 2", blue_train: "Station 1"]
}
]
我想计算给定模型铁路上的可用路线。
假设:
- 所有火车仅在称为火车站的定义点开始和停止。
- 火车在旅途中不会相撞。不用担心。
- 我们不必考虑火车的长度。我们假设它是一个火车头,它需要一个原子的space。
- 一个火车站只能停一列火车。
- 火车可以在同一个火车站起停。
所有火车的起始位置和结束位置都存储在地图中。所有排列都存储在一个列表中。示例:
iex(1)> Trains.list_routes(["ICE"], ["Hamburg", "Frankfurt"])
[
%{end: %{"ICE" => "Hamburg"}, start: %{"ICE" => "Hamburg"}},
%{end: %{"ICE" => "Frankfurt"}, start: %{"ICE" => "Frankfurt"}},
%{end: %{"ICE" => "Frankfurt"}, start: %{"ICE" => "Hamburg"}},
%{end: %{"ICE" => "Hamburg"}, start: %{"ICE" => "Frankfurt"}}
]
铁路模型可能如下所示(红色数字表示火车站):
对于该模型铁路上的两列火车,函数将以这种方式调用:
Trains.list_routes([:red_train, :blue_train], ["1", "2", "3", "4", "5"])
这是我当前的代码:
defmodule Trains do
@moduledoc """
Documentation for `Trains`.
"""
@doc """
Returns a list of all possible routes.
## Examples
iex> Trains.list_routes([:red_train, :blue_train], ["Station 1", "Station 2"])
[
%{
end: %{blue_train: "Station 2", red_train: "Station 1"},
start: %{blue_train: "Station 2", red_train: "Station 1"}
},
%{
end: %{blue_train: "Station 1", red_train: "Station 2"},
start: %{blue_train: "Station 1", red_train: "Station 2"}
},
%{
end: %{blue_train: "Station 1", red_train: "Station 2"},
start: %{blue_train: "Station 2", red_train: "Station 1"}
},
%{
end: %{blue_train: "Station 2", red_train: "Station 1"},
start: %{blue_train: "Station 1", red_train: "Station 2"}
}
]
"""
def list_routes([], []) do
[]
end
def list_routes([train], [station]) do
[
%{start: %{train => station}, end: %{train => station}}
]
end
def list_routes([train], [station1, station2]) do
[
%{start: %{train => station1}, end: %{train => station1}},
%{start: %{train => station2}, end: %{train => station2}},
%{start: %{train => station1}, end: %{train => station2}},
%{start: %{train => station2}, end: %{train => station1}}
]
end
def list_routes([train1, train2], [station1, station2]) do
[
%{
start: %{train1 => station1, train2 => station2},
end: %{train1 => station1, train2 => station2}
},
%{
start: %{train1 => station2, train2 => station1},
end: %{train1 => station2, train2 => station1}
},
%{
start: %{train1 => station1, train2 => station2},
end: %{train1 => station2, train2 => station1}
},
%{
start: %{train1 => station2, train2 => station1},
end: %{train1 => station1, train2 => station2}
}
]
end
def list_routes(trains, train_stations) do
# ???
end
end
当trains
的个数和train_stations
的个数都大于1时,如何遍历list_routes(trains, train_stations)
的所有组合?
根据您发布的代码,不清楚为什么一列火车允许相同的起点和终点站 %{start: %{train => station1}, end: %{train => station1}}
但两列火车不允许。
良好的开端应该是这样的:
iex|1 ▶ {trains, stations} =
{~w|red_train blue_train|a, ~w|1 2|}
#⇒ {[:red_train, :blue_train], ["1", "2"]}
iex|2 ▶ (for t1 <- trains, t2<- trains, t1 != t2,
s1 <- stations, s2 <- stations,
do: Enum.sort([{t1, s1}, {t2, s2}])
) |> Enum.uniq()
#⇒ [
# [blue_train: "1", red_train: "1"],
# [blue_train: "2", red_train: "1"],
# [blue_train: "1", red_train: "2"],
# [blue_train: "2", red_train: "2"]
# ]
无论如何,Kernel.SpecialForms.for/1
comprehension is your best friend here. Whether you need combinations and/or permutations, you might want to take a look at my Formulae
library, specifically at Formulae.Combinators
。
这是问题的解决方案。它使用 Formulae.
mix.exs
def deps do
[{:formulae, "~> 0.8"}]
end
lib/trains.ex
def list_routes([], []) do
[]
end
def list_routes(trains, train_stations)
when is_list(trains) and
is_list(train_stations) and
length(train_stations) >= length(trains) do
possible_states =
Enum.map(Formulae.permutations(train_stations, length(trains)), &Enum.zip(trains, &1))
for state_start <- possible_states, state_end <- possible_states do
%{start: state_start, end: state_end}
end
end
结果:
iex(1)> Trains.list_routes([:red_train, :blue_train], ["Station 1", "Station 2"])
[
%{
end: [red_train: "Station 1", blue_train: "Station 2"],
start: [red_train: "Station 1", blue_train: "Station 2"]
},
%{
end: [red_train: "Station 2", blue_train: "Station 1"],
start: [red_train: "Station 1", blue_train: "Station 2"]
},
%{
end: [red_train: "Station 1", blue_train: "Station 2"],
start: [red_train: "Station 2", blue_train: "Station 1"]
},
%{
end: [red_train: "Station 2", blue_train: "Station 1"],
start: [red_train: "Station 2", blue_train: "Station 1"]
}
]