如何将列表中的下一个日期时间与当前日期时间进行比较

Question

import os  
from datetime import datetime  

InFileName = r'path\Snapshot_list.txt'
#OutFileName = r'path\Process.bat'

InFile = open(InFileName)
for line in InFile:

s='20'
line = s[:2] + line[2:] [:6]
datetimeobject = datetime.strptime(line,'%Y%m%d')
newformat = datetimeobject.strftime('%Y-%m-%d')

print (newformat)

InFile.close()

我得到的格式是：

2012-05-30
2012-05-31
2012-06-01
2012-06-02
2012-06-03
2012-06-05

我想将每一行与之前的行进行比较，如果第 2 行！=第 1 + 1 行，那么我将在输出文件

中写入 'things'

Answer 1

from datetime import timedelta    

prev_date= None
for line in InFile:
    datetimeobject = datetime.strptime(line,'%Y%m%d')
    if datetimeobject-timedelta(days=1) != prev_date:
        outfile.write('things')
    prev_date= datetimeobject

如何将列表中的下一个日期时间与当前日期时间进行比较

How to compare next datetime in a list with the current one

python

datetime