合并Oracle中的两个查询并获取oracle中的数据

Question

我有两个查询结果低于每个 table

的数据

查询 1

查询 2

我需要组合这些查询并获取如下数据，因为我们看到帐户 ID (100) 确实存在，两个查询中的帐户 ID 都相同，从第一个查询中获取该帐户 ID 的行。

非常感谢任何帮助。

Answer 1

对于 SQL Server 和 Oracle 你都可以使用这种结构....

Select Address_ID, Display_Value, Account_ID
from FirstTable
union
Select Address_ID, Display_Value, Account_ID
from SecondTable
Where SecondTable.Account_ID not in (select FirstTable.Account_ID from FirstTable);

Answer 2

或者，完全外部联接可能会有所帮助。

SQL> with
  2  -- sample data
  3  t1 (address_id, display_value, account_id) as
  4    (select 1000, '10001 - Test 1', 100 from dual union all
  5     select 1000, '10002 - Test 2', 200 from dual union all
  6     select 1000, '10003 - Test 3', 300 from dual
  7    ),
  8  t2 (address_id, display_value, account_id) as
  9    (select 2000, '10001 - Test 1', 100 from dual union all
 10     select 3000, '10004 - Test 4', 400 from dual
 11    )
 12  --
 13  select nvl(a.address_id, b.address_id) address_id,
 14         nvl(a.display_value, b.display_value) display_value,
 15         nvl(a.account_id, b.account_id) account_id
 16  from t1 a full outer join t2 b on a.account_id = b.account_id;

ADDRESS_ID DISPLAY_VALUE  ACCOUNT_ID
---------- -------------- ----------
      1000 10001 - Test 1        100
      1000 10002 - Test 2        200
      1000 10003 - Test 3        300
      3000 10004 - Test 4        400

SQL>

合并Oracle中的两个查询并获取oracle中的数据

Combine Two Queries in Oracle and get the data in oracle

oracle

oracle11g