在Python3中可以做一个前面加0的十进制变量吗？

Question

我正在开展一个项目，该项目要求变量 s 等于 01234567。但是，每当我尝试运行程序时，它总是说

leading zeros in decimal literals are not permitted; use an 0o prefix for octal integers。 s 必须以零开头；有什么办法可以绕过这个错误吗？

k = list(int(input("What is the key? "))) # asks user for key
s = 01234567 # state to shuffle the numbers
# this line above is where the error takes place

#still a work in progress
def hash(s, k):
    i = 0
    j = 0
    for i < 8:
        j = (j + s(i) + k(i % 5)) % 8 # % performs mod
        # j makes a new j variable
        s(i), s(j) = s(j), s(i) # swaps the two variable values

hash (s, k) # hashes

Answer 1

首先，您应该让 k 和 s 成为一个整数列表。字符串是不可变的，因此您将无法就地编辑它们。此外，您需要使用方括号 ([]) 进行索引。您不能使用括号 (()) 进行索引。总计：

k = [int(c) for c in input("What is the key? ")] # asks user for key
s = [0,1,2,3,4,5,6,7] # state to shuffle the numbers
# this line above is where the error takes place

#still a work in progress
def hash(s, k):
    i = 0
    j = 0
    for i in range(8):
        j = (j + s[i] + k[i % 5]) % 8 # % performs mod
        # j makes a new j variable
        s[i], s[j] = s[j], s[i] # swaps the two variable values

hash (s, k) # hashes

print (s)

最后，您可能需要检查 k 的长度是否至少为 5 以防止索引错误。

在Python3中可以做一个前面加0的十进制变量吗？

Is it possible to make a decimal variable with a 0 in front of it in Python 3?

python

decimal