将 URL 解析为命令

Question

当我在终端中输入 git 回购 url 时，它有以下输出：

% https://github.com/chmln/sd.git        
zsh: no such file or directory: https://github.com/chmln/sd.git

我希望https://github.com/chmln/sd.git作为一个命令，它将

git clone https://github.com/chmln/sd.git
cd sd

我尝试了 preexec 钩子。

preexec () { 
    print ">>>preexec start<<<"
    # print -l ${(qqq)@}

    if  [[ ${(qqq)@} =~ ^https.* ]]
    then
    echo URL
    fi
    print ">>>preexec end<<<"

}

输出为

% https://github.com/chmln/sd.git
>>>preexec start<<<
>>>preexec end<<<
zsh: no such file or directory: https://github.com/chmln/sd.git

我该如何解决这个问题。

Answer 1

function _accept-line-with-url {

    if  [[ $BUFFER =~ ^https.*git ]]
    then

        echo $BUFFER >> $HISTFILE
        fc -R

        BUFFERz="git clone $BUFFER && cd $(basename $BUFFER .git)"
        zle .kill-whole-line
        BUFFER=$BUFFERz
        zle .accept-line
    else 
        zle .accept-line
    fi 
}

zle -N accept-line _accept-line-with-url

现在您可以在提示中粘贴 github url，它会克隆 repo。

将 URL 解析为命令

Parse URL as a Command

zsh