'is' 不是@JsonIgnore-d

Question

对于 Lombok 1.18.12 和 Jackson 2.11.0，此 POJO：

@Data @NoArgsConstructor
private static class MyPojo {
    private Long id = 1L;
    private boolean isGood = true;
    @JsonIgnore
    private boolean isIgnored = false;

}

没有忽略isIgnored字段所以测试失败：

@Test
public void serializePojo() throws IOException {
    ObjectMapper objectMapper = new ObjectMapper();
    MyPojo pojo = new MyPojo();
    String actualJson = objectMapper.writeValueAsString(pojo);
    String expectedJson = "{\"id\":1,\"good\":true}";

    assertThat(actualJson).asString().isEqualToIgnoringWhitespace(expectedJson);
}

因为实际的JSON是：

JSON{"id":1,"ignored":false,"good":true}

Answer 1

一个解决方案是将 @JsonIgnore 添加到显式 getter:

@Data @NoArgsConstructor
private static class MyPojo {
    private Long id = 1L;
    private boolean isGood = true;
    private boolean isIgnored = true;

    @JsonIgnore
    public boolean isIgnored() {
        return isIgnored;
    }

}

一种解决方法是避免在布尔属性上使用（常见的）is 前缀：

@Data @NoArgsConstructor
private static class MyPojo {
    private Long id = 1L;
    private boolean isGood = true;
    @JsonIgnore
    private boolean ignored = true;

}

'is' 不是@JsonIgnore-d

'is' not @JsonIgnore-d

java

serialization

jackson

lombok