写一个查询来查找租借科幻电影超过 2 次的客户的全名并按字母顺序排列

Question

我正在尝试回答上述问题，但我的输出与预期输出不同。我的代码如下所示，

select distinct concat(first_name, ' ', last_name) as Customer_name
from customer c
inner join rental r on r.customer_id = c.customer_id
inner join inventory i on i.inventory_id = r.inventory_id
inner join film f on f.film_id = i.film_id
inner join film_category fc on fc.film_id = f.film_id
inner join category ca on ca.category_id = fc.category_id
where name = 'sci-fi' and rental_id > 2
order by Customer_name

Answer 1

按客户名称聚合，然后从 HAVING 子句断言计数为 2 或更大：

select concat(first_name, ' ', last_name) as Customer_name
from customer c
inner join rental r on r.customer_id = c.customer_id
inner join inventory i on i.inventory_id = r.inventory_id
inner join film f on f.film_id = i.film_id
inner join film_category fc on fc.film_id = f.film_id
inner join category ca on ca.category_id = fc.category_id
where name = 'sci-fi' and rental_id > 2
group by Customer_name
having count(*) > 2
order by Customer_name;

写一个查询来查找租借科幻电影超过 2 次的客户的全名并按字母顺序排列

Write a query to find the full names of customers who have rented sci-fi movies more than 2 times and arrange alphabetically

mysql

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