国家等的 XSLT 特殊字符

Question

我的 XSLT 映射有一个小问题。

我得到一个 XML 文件作为输入，其中包含以下数据：

<?xml version="1.0" encoding="UTF-8"?>
<Request>
    <Query>
        <Parameter name="staat">OESTERREICH</Parameter>
    </Query>
</Request>

我正在尝试获取状态并为 OE、UE、AE 和 SS 设置特殊字符。

特殊字符：

OE = Ö
UE = Ü
AE = Ä
SS = ẞ

我试过的是下面的 XSLT Script/Mapping:'

<?xml version="1.0" encoding="UTF-8"?><?xe.source ../TemporaryFiles/Test_XML_1.xml#Request?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
    <xsl:output media-type="text/xml" method="xml"></xsl:output>
    <xsl:template match="/">
        <root>
        <first_two_letters>
            <xsl:value-of select="substring(upper-case(/Request/Query/Parameter[@name='staat']),1,2)"></xsl:value-of>
        </first_two_letters>
        <xsl:choose>
            <xsl:when test="substring(/Request/Query/Parameter[@name='staat'],1,2)='OE'">
                <xsl:value-of select="concat(substring(replace(/Request/Query/Parameter[@name='staat2'], 'OE', 'Ö'),1,2), substring(replace(replace(replace(lower-case(/Request/Query/Parameter[@name='staat2']), 'ae', 'ä'), 'oe', 'ö'), 'ue', 'ü'),3))"></xsl:value-of>
            </xsl:when>
            <xsl:when test="substring(/Request/Query/Parameter[@name='staat'],1,2)='AE'">
                <xsl:value-of select="concat(substring(replace(/Request/Query/Parameter[@name='staat2'], 'AE', ''),1,2), substring(replace(replace(replace(lower-case(/Request/Query/Parameter[@name='staat2']), 'ae', 'ä'), 'oe', 'ö'), 'ue', 'ü'),3))"></xsl:value-of>
            </xsl:when>
            <xsl:when test="substring(/Request/Query/Parameter[@name='staat'],1,2)='UE'">
                <xsl:value-of select="concat(substring(replace(/Request/Query/Parameter[@name='staat2'], 'UE', 'Ü'),1,2), substring(replace(replace(replace(lower-case(/Request/Query/Parameter[@name='staat2']), 'ae', 'ä'), 'oe', 'ö'), 'ue', 'ü'),3))"></xsl:value-of>
            </xsl:when>
            <xsl:when test="substring(/Request/Query/Parameter[@name='staat'],1,2)='SS'">
                <xsl:value-of select="concat(substring(replace(/Request/Query/Parameter[@name='staat2'], 'SS', 'ẞ'),1,2), substring(replace(replace(replace(lower-case(/Request/Query/Parameter[@name='staat2']), 'ae', 'ä'), 'oe', 'ö'), 'ss', 'ß'),3))"></xsl:value-of>
            </xsl:when>
            <xsl:otherwise>
                <xsl:value-of select="concat(substring(/Request/Query/Parameter[@name='staat2'],1,1), substring(replace(replace(replace(lower-case(/Request/Query/Parameter[@name='staat2']), 'ae', 'ä'), 'oe', 'ö'), 'ue', 'ü'),2))"></xsl:value-of>
            </xsl:otherwise>
        </xsl:choose>
        </root>
    </xsl:template>
</xsl:stylesheet>

脚本运行良好，但输出是：

<root>
    <first_two_letters>OE</first_two_letters>
</root>

我真正期望的输出是：

<root>
    <first_two_letters>OE</first_two_letters>
    Österreich
</root>

- -编辑： - -

在命令中的@Boldewyn 小帮助之后，这里是工作代码：

<?xml version="1.0" encoding="UTF-8"?><?xe.source ../TemporaryFiles/Test_XML_1.xml#Request?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
    <xsl:output media-type="text/xml" method="xml"></xsl:output>
    <xsl:template match="/">
        <root>
        <first_two_letters>
            <xsl:value-of select="substring(upper-case(/Request/Query/Parameter[@name='staat']),1,2)"></xsl:value-of>
        </first_two_letters>
        <xsl:choose>
            <xsl:when test="substring(/Request/Query/Parameter[@name='staat'],1,2)='OE'">
                <xsl:value-of select="concat(substring(replace(/Request/Query/Parameter[@name='staat'], 'OE', 'Ö'),1,1), substring(replace(replace(replace(lower-case(/Request/Query/Parameter[@name='staat']), 'ae', 'ä'), 'oe', 'ö'), 'ue', 'ü'),2))"></xsl:value-of>
            </xsl:when>
            <xsl:when test="substring(/Request/Query/Parameter[@name='staat'],1,2)='AE'">
                <xsl:value-of select="concat(substring(replace(/Request/Query/Parameter[@name='staat'], 'AE', ''),1,1), substring(replace(replace(replace(lower-case(/Request/Query/Parameter[@name='staat']), 'ae', 'ä'), 'oe', 'ö'), 'ue', 'ü'),2))"></xsl:value-of>
            </xsl:when>
            <xsl:when test="substring(/Request/Query/Parameter[@name='staat'],1,2)='UE'">
                <xsl:value-of select="concat(substring(replace(/Request/Query/Parameter[@name='staat'], 'UE', 'Ü'),1,1), substring(replace(replace(replace(lower-case(/Request/Query/Parameter[@name='staat']), 'ae', 'ä'), 'oe', 'ö'), 'ue', 'ü'),2))"></xsl:value-of>
            </xsl:when>
            <xsl:when test="substring(/Request/Query/Parameter[@name='staat'],1,2)='SS'">
                <xsl:value-of select="concat(substring(replace(/Request/Query/Parameter[@name='staat'], 'SS', 'ẞ'),1,1), substring(replace(replace(replace(lower-case(/Request/Query/Parameter[@name='staat']), 'ae', 'ä'), 'oe', 'ö'), 'ue', 'ü'),2))"></xsl:value-of>
            </xsl:when>
            <xsl:otherwise>
                <xsl:value-of select="concat(substring(/Request/Query/Parameter[@name='staat'],1,1), substring(replace(replace(replace(lower-case(/Request/Query/Parameter[@name='staat']), 'ae', 'ä'), 'oe', 'ö'), 'ue', 'ü'),2))"></xsl:value-of>
            </xsl:otherwise>
        </xsl:choose>
        </root>
    </xsl:template>
</xsl:stylesheet>

但现在我明白了评论中所说的问题：

Israel = Isräl.

[2020-08-06 16:26]：我的意思是，他们是一些例外，比如以色列或立陶宛，特殊字符不应该生效。

我现在该如何解决这个问题？

Answer 1

这里有一种方法可以做到这一点。（我不会说德语，所以不确定这是否适用于所有情况！）我已修改您的输入以添加更多测试用例。

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    version="2.0">

  <xsl:mode on-no-match="shallow-copy"/>

  <xsl:output method="xml" indent="yes"/>
  
  <xsl:template match="/">
    <root>
      <xsl:apply-templates select="Request/Query/Parameter[@name='staat']"/>
    </root>
  </xsl:template>

  <xsl:template match="Parameter">
      <xsl:variable name="text" select="."/>
      <xsl:variable name="upper2" select="upper-case(substring($text,1,2))"/>
      <first_two_letters>
        <xsl:value-of select="substring(upper-case($text),1,2)"></xsl:value-of>
      </first_two_letters>
      <!-- Replacement in first 2 characters -->
      <xsl:value-of select="if($upper2='OE' or $upper2='AE' or $upper2='UE' or $upper2='SE')
                            then replace(replace(replace(replace(upper-case(substring($text,1,2)),'OE','Ö'),'AE','Ä'),'UE','Ü'),'SS','ẞ')
                            else substring($text,1,2)"/>
      <!-- Replacement in remainging characters -->
      <xsl:value-of select="replace(replace(replace(lower-case(substring($text,3,string-length($text)-2)), 'ae', 'ä'), 'oe', 'ö'), 'ss', 'ß')"/>
  </xsl:template>
  
</xsl:stylesheet>

看到它在这里工作：https://xsltfiddle.liberty-development.net/3Mvnt3M

国家等的 XSLT 特殊字符

XSLT special character for countrys etc

xml

xslt

xslt-2.0