PostgreSQL:为所有行创建具有唯一时间戳的 table
PostgreSQL: create table with unique timestamp for all rows
我在 table 中有 begin/end 个位置和时间的用户旅行记录,如下所示:
CREATE TABLE trips(id integer, start_timestamp timestamp with time zone,
session_id integer, start_lat double precision,
start_lon double precision, end_lat double precision,
end_lon double precision, mode integer);
INSERT INTO trips (id, start_timestamp, session_id, start_lat,start_lon,end_lat,end_lon,mode)
VALUES (563097015,'2017-05-20 17:47:12+01', 128618, 41.1783308,-8.5949878, 41.1784478, -8.5948463, 0),
(563097013, '2017-05-20 17:45:29+01', 128618, 41.1781344, -8.5951169, 41.1782919, -8.5950689, 0),
(563097011, '2017-05-20 17:43:41+01', 128618, 41.1781196, -8.5954075, 41.1782139, -8.5950689, 0),
(563097009, '2017-05-20 17:41:48+01', 128618, 41.1782497, -8.595197, 41.1781101, -8.5954124, 0),
(563097003, '2017-05-20 17:10:29+01', 128618, 41.1832512, -8.6081606, 41.1782561, -8.5950259, 0)
第二个 table 是所有行程的原始 gps 轨迹记录,类似于:
CREATE TABLE gps_traces (session_id integer, seconds integer, lat double precision,
lon double precision, speed double precision);
INSERT INTO gps_traces (session_id, seconds , lat , lon , speed )
VALUES (128618,1495296443,41.1844471,-8.6065158,1.35148),
(128618,1495296444,41.1844482,-8.6065303,1.28004),
(128618,1495296445,41.1844572,-8.6065503,1.46086),
(128618,1495296446,41.1844541,-8.6065691,1.23),
(128618,1495296446,41.1844589,-8.6065861, 1.22919),
(128618,1495296447,41.1844587, -8.6066043, 1.30188),
(128618, 1495296448, 41.1844604, -8.6066261, 1.43126),
(128618, 1495296449, 41.184471, -8.6066412, 1.55003),
(128618,1495296450, 41.1844715, -8.6066572, 1.29062),
(128618,1495296450, 41.1844707, -8.6066736, 1.3618)
据此我想创建一个新的 table mytable
,其中包含 GPS 在 session_id
上连接这些 table,如下所示:
CREATE TABLE mytable AS SELECT id, seconds, lat, lon, speed, mode
FROM trips t
JOIN gps_traces g
ON t.session_id=g.session_id
然而,在新的 table 中,我想确保对于在同一个 unix 时间戳中记录两次的行,只有 only 被选入我的新 table。例如在这种情况下:
SELECT * FROM mytable WHERE id = 563097003;
+-----------+------------+------------+------------+---------+------+
| id | seconds | lat | lon | speed | mode |
+-----------+------------+------------+------------+---------+------+
| 563097003 | 1495296443 | 41.1844471 | -8.6065158 | 1.35148 | 0 |
| 563097003 | 1495296444 | 41.1844482 | -8.6065303 | 1.28004 | 0 |
| 563097003 | 1495296445 | 41.1844572 | -8.6065503 | 1.46086 | 0 |
| 563097003 | 1495296446 | 41.1844541 | -8.6065691 | 1.23 | 0 |
| 563097003 | 1495296446 | 41.1844589 | -8.6065861 | 1.22919 | 0 |
| 563097003 | 1495296447 | 41.1844587 | -8.6066043 | 1.30188 | 0 |
| 563097003 | 1495296448 | 41.1844604 | -8.6066261 | 1.43126 | 0 |
| 563097003 | 1495296449 | 41.184471 | -8.6066412 | 1.55003 | 0 |
| 563097003 | 1495296450 | 41.1844715 | -8.6066572 | 1.29062 | 0 |
| 563097003 | 1495296450 | 41.1844707 | -8.6066736 | 1.3618 | 0 |
| 10 rows | | | | | |
+-----------+------------+------------+------------+---------+------+
第 seconds
列是 Unix 时间戳。如图所示,我们可以看到在 1495296446
和 1495296450
处有超过 1 个唯一时间戳计数的行。我想确保对于每次旅行,记录都被选择到具有唯一时间戳的新 table 中(因此在上述情况下,只有一个记录应该被选择到新的 table 中)。我在 db<>fiddle.
中说明了这一点
编辑
预期输出:
+-----------+------------+------------+------------+---------+------+
| id | seconds | lat | lon | speed | mode |
+-----------+------------+------------+------------+---------+------+
| 563097003 | 1495296443 | 41.1844471 | -8.6065158 | 1.35148 | 0 |
| 563097003 | 1495296444 | 41.1844482 | -8.6065303 | 1.28004 | 0 |
| 563097003 | 1495296445 | 41.1844572 | -8.6065503 | 1.46086 | 0 |
| 563097003 | 1495296446 | 41.1844541 | -8.6065691 | 1.23 | 0 |
| 563097003 | 1495296447 | 41.1844587 | -8.6066043 | 1.30188 | 0 |
| 563097003 | 1495296448 | 41.1844604 | -8.6066261 | 1.43126 | 0 |
| 563097003 | 1495296449 | 41.184471 | -8.6066412 | 1.55003 | 0 |
| 563097003 | 1495296450 | 41.1844715 | -8.6066572 | 1.29062 | 0 |
| 8 rows | | | | | |
+-----------+------------+------------+------------+---------+------+
使用DISTINCT ON
:
CREATE TABLE mytable AS
SELECT DISTINCT ON (t.session_id, seconds) id, seconds, lat, lon, speed, mode
FROM trips t JOIN
gps_traces g
ON t.session_id = g.session_id
ORDER BY t.session_id, seconds;
注意:我希望您在新的 table 中也包含 session_id
。
感谢@Abelisto,事实证明对此答案的以下修改按预期工作。
CREATE TABLE mytable AS SELECT DISTINCT ON (id, seconds)id,
seconds, lat, lon, speed, mode
FROM trips t
JOIN gps_traces g
ON t.session_id=g.session_id
ORDER BY id, seconds
Here 是一个 db<>fiddle.
我在 table 中有 begin/end 个位置和时间的用户旅行记录,如下所示:
CREATE TABLE trips(id integer, start_timestamp timestamp with time zone,
session_id integer, start_lat double precision,
start_lon double precision, end_lat double precision,
end_lon double precision, mode integer);
INSERT INTO trips (id, start_timestamp, session_id, start_lat,start_lon,end_lat,end_lon,mode)
VALUES (563097015,'2017-05-20 17:47:12+01', 128618, 41.1783308,-8.5949878, 41.1784478, -8.5948463, 0),
(563097013, '2017-05-20 17:45:29+01', 128618, 41.1781344, -8.5951169, 41.1782919, -8.5950689, 0),
(563097011, '2017-05-20 17:43:41+01', 128618, 41.1781196, -8.5954075, 41.1782139, -8.5950689, 0),
(563097009, '2017-05-20 17:41:48+01', 128618, 41.1782497, -8.595197, 41.1781101, -8.5954124, 0),
(563097003, '2017-05-20 17:10:29+01', 128618, 41.1832512, -8.6081606, 41.1782561, -8.5950259, 0)
第二个 table 是所有行程的原始 gps 轨迹记录,类似于:
CREATE TABLE gps_traces (session_id integer, seconds integer, lat double precision,
lon double precision, speed double precision);
INSERT INTO gps_traces (session_id, seconds , lat , lon , speed )
VALUES (128618,1495296443,41.1844471,-8.6065158,1.35148),
(128618,1495296444,41.1844482,-8.6065303,1.28004),
(128618,1495296445,41.1844572,-8.6065503,1.46086),
(128618,1495296446,41.1844541,-8.6065691,1.23),
(128618,1495296446,41.1844589,-8.6065861, 1.22919),
(128618,1495296447,41.1844587, -8.6066043, 1.30188),
(128618, 1495296448, 41.1844604, -8.6066261, 1.43126),
(128618, 1495296449, 41.184471, -8.6066412, 1.55003),
(128618,1495296450, 41.1844715, -8.6066572, 1.29062),
(128618,1495296450, 41.1844707, -8.6066736, 1.3618)
据此我想创建一个新的 table mytable
,其中包含 GPS 在 session_id
上连接这些 table,如下所示:
CREATE TABLE mytable AS SELECT id, seconds, lat, lon, speed, mode
FROM trips t
JOIN gps_traces g
ON t.session_id=g.session_id
然而,在新的 table 中,我想确保对于在同一个 unix 时间戳中记录两次的行,只有 only 被选入我的新 table。例如在这种情况下:
SELECT * FROM mytable WHERE id = 563097003;
+-----------+------------+------------+------------+---------+------+
| id | seconds | lat | lon | speed | mode |
+-----------+------------+------------+------------+---------+------+
| 563097003 | 1495296443 | 41.1844471 | -8.6065158 | 1.35148 | 0 |
| 563097003 | 1495296444 | 41.1844482 | -8.6065303 | 1.28004 | 0 |
| 563097003 | 1495296445 | 41.1844572 | -8.6065503 | 1.46086 | 0 |
| 563097003 | 1495296446 | 41.1844541 | -8.6065691 | 1.23 | 0 |
| 563097003 | 1495296446 | 41.1844589 | -8.6065861 | 1.22919 | 0 |
| 563097003 | 1495296447 | 41.1844587 | -8.6066043 | 1.30188 | 0 |
| 563097003 | 1495296448 | 41.1844604 | -8.6066261 | 1.43126 | 0 |
| 563097003 | 1495296449 | 41.184471 | -8.6066412 | 1.55003 | 0 |
| 563097003 | 1495296450 | 41.1844715 | -8.6066572 | 1.29062 | 0 |
| 563097003 | 1495296450 | 41.1844707 | -8.6066736 | 1.3618 | 0 |
| 10 rows | | | | | |
+-----------+------------+------------+------------+---------+------+
第 seconds
列是 Unix 时间戳。如图所示,我们可以看到在 1495296446
和 1495296450
处有超过 1 个唯一时间戳计数的行。我想确保对于每次旅行,记录都被选择到具有唯一时间戳的新 table 中(因此在上述情况下,只有一个记录应该被选择到新的 table 中)。我在 db<>fiddle.
编辑
预期输出:
+-----------+------------+------------+------------+---------+------+
| id | seconds | lat | lon | speed | mode |
+-----------+------------+------------+------------+---------+------+
| 563097003 | 1495296443 | 41.1844471 | -8.6065158 | 1.35148 | 0 |
| 563097003 | 1495296444 | 41.1844482 | -8.6065303 | 1.28004 | 0 |
| 563097003 | 1495296445 | 41.1844572 | -8.6065503 | 1.46086 | 0 |
| 563097003 | 1495296446 | 41.1844541 | -8.6065691 | 1.23 | 0 |
| 563097003 | 1495296447 | 41.1844587 | -8.6066043 | 1.30188 | 0 |
| 563097003 | 1495296448 | 41.1844604 | -8.6066261 | 1.43126 | 0 |
| 563097003 | 1495296449 | 41.184471 | -8.6066412 | 1.55003 | 0 |
| 563097003 | 1495296450 | 41.1844715 | -8.6066572 | 1.29062 | 0 |
| 8 rows | | | | | |
+-----------+------------+------------+------------+---------+------+
使用DISTINCT ON
:
CREATE TABLE mytable AS
SELECT DISTINCT ON (t.session_id, seconds) id, seconds, lat, lon, speed, mode
FROM trips t JOIN
gps_traces g
ON t.session_id = g.session_id
ORDER BY t.session_id, seconds;
注意:我希望您在新的 table 中也包含 session_id
。
感谢@Abelisto,事实证明对此答案的以下修改按预期工作。
CREATE TABLE mytable AS SELECT DISTINCT ON (id, seconds)id,
seconds, lat, lon, speed, mode
FROM trips t
JOIN gps_traces g
ON t.session_id=g.session_id
ORDER BY id, seconds
Here 是一个 db<>fiddle.