从 case 语句 C# 中获取数据
Get data out of case statement C#
我正在使用我们购买的热像仪的 SDK。实际上我是一名 PHP Web 开发人员,现在我必须在 .Net 中编写代码
所以有一个案例,但我真的不知道如何从中获取数据。
private void OnDetect(CallbackEventArgument callbackArgument)
{
var detectionResult = callbackArgument.GetDetectionResult();
var firstDetection = detectionResult.Sequence.Items.First();
var message = string.Empty;
ImageArgument fullSizeImage = null;
switch (detectionResult.Type)
{
case T3DDetectionType.OBSERVATION:
message = "Track ID: " + firstDetection.TrackId;
fullSizeImage = detectionResult.RGBImage;
break;
case T3DDetectionType.DEPTH_LIVENESS:
case T3DDetectionType.THERMAL_LIVENESS:
message = "Track ID: " + firstDetection.TrackId + " Score: " + (firstDetection as Liveness).Score.ToString("N0");
fullSizeImage = detectionResult.FullImage;
break;
case T3DDetectionType.TEMPERATURE:
message = "Temperature: " + (firstDetection as Temperature).MeasurementValueCelsius.ToString("N1") + "°C";
fullSizeImage = detectionResult.FullImage;
break;
}
所以我想做的是能够在 case 之后获取 (firstDetection as Liveness).Score.ToString("N0")
、firstDetection.TrackId
和 (firstDetection as Temperature).MeasurementValueCelsius.ToString("N1") + "°C"
的数据并创建一个 JSON。
创建 json 有效,但我就是无法调用数据。
如果你想从你的 switch 语句中得到一些东西,那么只需执行以下操作:
- 在 switch 语句之前声明一个变量
string firstDetection = string.Empty;
- 然后将您需要的值分配给 switch case 中的那个变量。
case T3DDetectionType.TEMPERATURE:
message = "Temperature: " + (firstDetection as Temperature).MeasurementValueCelsius.ToString("N1") + "°C";
firstDetection = (firstDetection as Temperature).MeasurementValueCelsius.ToString("N1") + "°C";
fullSizeImage = detectionResult.FullImage;
break;
现在,在 switch 语句之后,您将在变量 firstDetection
中获得所需的值。
我正在使用我们购买的热像仪的 SDK。实际上我是一名 PHP Web 开发人员,现在我必须在 .Net 中编写代码
所以有一个案例,但我真的不知道如何从中获取数据。
private void OnDetect(CallbackEventArgument callbackArgument)
{
var detectionResult = callbackArgument.GetDetectionResult();
var firstDetection = detectionResult.Sequence.Items.First();
var message = string.Empty;
ImageArgument fullSizeImage = null;
switch (detectionResult.Type)
{
case T3DDetectionType.OBSERVATION:
message = "Track ID: " + firstDetection.TrackId;
fullSizeImage = detectionResult.RGBImage;
break;
case T3DDetectionType.DEPTH_LIVENESS:
case T3DDetectionType.THERMAL_LIVENESS:
message = "Track ID: " + firstDetection.TrackId + " Score: " + (firstDetection as Liveness).Score.ToString("N0");
fullSizeImage = detectionResult.FullImage;
break;
case T3DDetectionType.TEMPERATURE:
message = "Temperature: " + (firstDetection as Temperature).MeasurementValueCelsius.ToString("N1") + "°C";
fullSizeImage = detectionResult.FullImage;
break;
}
所以我想做的是能够在 case 之后获取 (firstDetection as Liveness).Score.ToString("N0")
、firstDetection.TrackId
和 (firstDetection as Temperature).MeasurementValueCelsius.ToString("N1") + "°C"
的数据并创建一个 JSON。
创建 json 有效,但我就是无法调用数据。
如果你想从你的 switch 语句中得到一些东西,那么只需执行以下操作:
- 在 switch 语句之前声明一个变量
string firstDetection = string.Empty;
- 然后将您需要的值分配给 switch case 中的那个变量。
case T3DDetectionType.TEMPERATURE:
message = "Temperature: " + (firstDetection as Temperature).MeasurementValueCelsius.ToString("N1") + "°C";
firstDetection = (firstDetection as Temperature).MeasurementValueCelsius.ToString("N1") + "°C";
fullSizeImage = detectionResult.FullImage;
break;
现在,在 switch 语句之后,您将在变量 firstDetection
中获得所需的值。