将所有 While 输出回显到单个变量中

Question

这是我的代码：

$sql = "SELECT * FROM notifications";
if($result = mysqli_query($link, $sql)) {
    if(mysqli_num_rows($result) > 0) {  
        while($row = mysqli_fetch_array($result)) {
            $notification = "
<a class='d-flex align-items-center dropdown-item' href=".$row["link"].">
<div class='dropdown-list-image mr-3'><i class='fas fa-bell'></i>
<div class='bg-success status-indicator'></div>
</div>
<div class='font-weight-bold'>
<div class='text-truncate'><span>".$row["omschrijving"].".</span></div>
<p class='small text-gray-500 mb-0'>".$row["klant"]." - ".$row["createdat"]."</p>
</div>
</a>    
";
        }
    }
}

在我的页面中还有：

echo "<h6 class='dropdown-header'>Notificaties</h6>
$notification"

出于不同的原因，我真的很想将输出作为单个变量。

现在只从数据库输出第一个通知。

是否可以这样做：为 table 中的每一行回显 $notification？

Answer 1

连接通知可能会做到这一点

$notification = '';
while($row = mysqli_fetch_array($result))
    $notification .="
        <a class='d-flex align-items-center dropdown-item' href=".$row["link"].">
        <div class='dropdown-list-image mr-3'><i class='fas fa-bell'></i>
        <div class='bg-success status-indicator'></div>
        </div>
        <div class='font-weight-bold'>
        <div class='text-truncate'><span>".$row["omschrijving"].".</span></div>
        <p class='small text-gray-500 mb-0'>".$row["klant"]." - ".$row["createdat"]."</p>
        </div>
        </a>   ";

Answer 2

看起来您在 while 循环中的每个实例都覆盖了 $notification 变量。您应该查看 concatenating that variable. Additionally you want to be aware that HTML inside a PHP variable may not always play nice. I would also recommend using heredoc 语法。它看起来像这样：

$notification .= <<<EOD
HTML goes here
EOD;

将所有 While 输出回显到单个变量中

Echo all While outputs into a single variable

php

variables

mysqli

if-statement

while-loop