从两个给定时间获取 hh:mm 格式时间的更好选择

Question

select cast(datediff(minute,convert(time,'09:35 AM'),
       convert(time,'07:06 PM'))/60 as varchar)
       +':'+cast(datediff(minute,convert(time,'09:35 AM'),
       convert(time,'07:06 PM'))%60 as varchar)

输出 : 9:31

我们有没有其他功能可以缩短上面的脚本。另外，我应该怎么做才能得到 09:31 而不是 9:31 的输出？

Answer 1

您可以在 Sql 服务器中使用 Format 功能。

更新 -（示例）：这可能是您想要的：

select FORMAT(CONVERT(datetime,'9:31'),'HH:mm') AS 'time'

Answer 2

您可以将 CONVERT() 与样式 114 一起使用以获得 HH:mm

SELECT 
    CONVERT(nvarchar(5), 
        -- Get difference of time
        CONVERT(datetime,'07:06 PM') - CONVERT(datetime,'09:35 AM')
        , 114)

SQL Fiddle

编辑

作为避免日期时间算法的注释

SELECT CONVERT(varchar(5), 
        DATEADD(minute, 
            DATEDIFF(minute, convert(time,'09:35 AM'), convert(time,'07:06 PM')) 
        , 0)
    , 114)

Answer 3

DECLARE @time1 AS VARCHAR(8) = '09:35 AM'
DECLARE @time2 AS VARCHAR(8) = '07:06 PM'
    
SELECT 
    time1   = CAST(@time1 AS TIME), 
    time2   = CAST(@time2 AS TIME),
    diff    = DATEDIFF(MINUTE, @time1, @time2),
    hh      = RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))/60 AS VARCHAR(2)), 2),
    mm      = RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))%60 AS VARCHAR(2)), 2),
    final   = RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))/60 AS VARCHAR(2)), 2) + ':' +
              RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))%60 AS VARCHAR(2)), 2)

当声明and/or转换为VARCHAR类型时，您应该指定长度，否则SQL-服务器会为您分配一个默认值。有时是 1，有时是 30。有关详细信息，请参阅此 article。

另外，要将差异格式化为 hh:mm，您需要用适当数量的零填充字符串。这是使用 :

RIGHT('00' + str, 2)

Answer 4

试试这个广告，看看这是否是您想要的：

SELECT FORMAT(GETDATE(),'hh:mm')

或

SELECT (CONVERT(VARCHAR(5), GETDATE(), 114))

从两个给定时间获取 hh:mm 格式时间的更好选择

Better option to get time in hh:mm format from two given time

sql

sql-server

time

sql-server-2008