table 中的多个字段只有 return 个异常

Question

我有 table（交易）存储零售交易。我希望能够找到多个字段的独特组合。我有一个 table 存储交易类型（在线或商店）和客户名称、周数和产品类型。我需要找到共享相同客户、周和产品的在线或商店交易，但前提是没有来自其他交易类型的相应交易。请参阅下面的示例 ...

+------------------+----------+------+--------------+
| Transaction_Type | Customer | Week | Product_Type |
+------------------+----------+------+--------------+
| Online           | 123      | 1    | Clothing     |
+------------------+----------+------+--------------+
| Store            | 123      | 1    | Homeware     |
+------------------+----------+------+--------------+
| Online           | 123      | 1    | Homeware     |
+------------------+----------+------+--------------+
| Online           | 123      | 2    | Clothing     |
+------------------+----------+------+--------------+
| Store            | 123      | 2    | Clothing     |
+------------------+----------+------+--------------+
| Online           | 123      | 2    | Sporting     |
+------------------+----------+------+--------------+
| Online           | 345      | 2    | Clothing     |
+------------------+----------+------+--------------+
| Store            | 345      | 2    | Homeware     |
+------------------+----------+------+--------------+
| Online           | 345      | 2    | Homeware     |
+------------------+----------+------+--------------+
| Online           | 345      | 2    | Clothing     |
+------------------+----------+------+--------------+
| Store            | 345      | 2    | Homeware     |
+------------------+----------+------+--------------+
| Online           | 345      | 2    | Sporting     |
+------------------+----------+------+--------------+

由此我想看到以下返回...

+------------------+----------+------+--------------+
| Transaction_Type | Customer | Week | Product_Type |
+------------------+----------+------+--------------+
| Online           | 123      | 1    | Clothing     |
+------------------+----------+------+--------------+
| Online           | 123      | 2    | Clothing     |
+------------------+----------+------+--------------+
| Online           | 345      | 2    | Clothing     |
+------------------+----------+------+--------------+
| Online           | 345      | 2    | Clothing     |
+------------------+----------+------+--------------+
| Online           | 345      | 2    | Clothing     |
+------------------+----------+------+--------------+
| Store            | 345      | 2    | Homeware     |
+------------------+----------+------+--------------+
| Online           | 345      | 2    | Sporting     |
+------------------+----------+------+--------------+

其他交易被排除在外，因为在线和商店具有相同的客户、周和 product_type 值。

我目前的代码是这样的...

select * from transactions
group by customer, week, product_type
having count(customer, week, product_type) <> 2

但我想我应该使用分区，但我不知道如何使用。

谢谢

Answer 1

您可以使用 not exists:

select t.*
from transactions t
where not exists (
    select 1
    from transactions t1
    where 
        t1.customer = t.customer
        and t1.week = t.week
        and t1.product = t.product
        and t1.transaction_type <> t.transaction_type
)

table 中的多个字段只有 return 个异常

Only return exceptions from multiple fields in a table

sql

oracle

count

subquery

oracle11g