从 table B 中删除列值类似于 table a 的通配符

Question

所以我有两个表

seeds
- id
- domain

subdomain
- id 
- domain
- ip

我想根据域过滤子域

例如

seeds
Id  Domain
0   google.com
1   test.com

subdomain
Id   domain          ip
0    test.google.com    null
1    api.google.com     null
2    dnr.com            null
3    neverssl.com       null

我正在尝试编写一个查询来删除 subdomain 中不包含来自 seeds

的 domain 的行

What have you tried?

delete subdomain 
where id not in 
(select subs.id from seed as seeds 
join 
subdomain as subs on subs.domain 
like concat('%', seeds.domain));

和

delete subdomain 
where id not in
(SELECT sd.id
FROM subdomain sd
LEFT JOIN seed s
  ON sd.domain LIKE CONCAT('%', s.Domain)
WHERE s.id IS NULL)

这两个查询都只是删除所有行

Answer 1

您可以使用 not exists:

delete from subdomain
where not exists (
    select 1
    from seeds s
    where subdomain.domain like concat('%', s.domain)
)

DEMO

Answer 2

使用 LEFT JOIN + NULL 模式查找不匹配的行。

DELETE d
FROM subdomain AS d
LEFT JOIN seeds AS s ON d.domain LIKE CONCAT('%', s.domain)
WHERE s.id IS NULL

DEMO