如何在没有未知密钥的情况下访问 Json 数据?
How to access Json data without unknown key?
public static string RESTToJsonConverter(string incoming_data){
string data = "[";
int i = 0;
Debug.Log("incoming_data"+incoming_data);
data += "]";
string JSONToParse = "{\"values\":" + data + "}";
return JSONToParse;
}
下面是我 运行 该代码时的结果。我的问题是如何在不使用 "M4qRmfIqhKdy643Ujye"
密钥(自动生成)的情况下 access/get 所有数据?
如果使用 JavaScript,我可以使用 object.values
但是因为我使用的是 C#,所以我不知道如何获取数据。
{
"-M4qRmfIqhKdy643Ujye": {
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bob",
"objName": "Bobby",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
},
"-M4qRmfIqhKdy643Ujye": {
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bobfds",
"objName": "Bobbydsf",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
},
"-M4qRmfIqhKdy643Ujye": {
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bobfdsa",
"objName": "Bobbyfc",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
}
}
更新
这是我的下载器中的功能之一Class
IEnumerator DownloadData(string dataPath, Action<string> callback){
Debug.Log("dataPath=>"+dataPath);
var token = LocalData.getAuth();
Auth data = JsonUtility.FromJson<Auth>(token);
var request = new
UnityWebRequest("https://test123.firebaseio.com/"+dataPath+".json?
auth="+data.idToken, "GET");
request.downloadHandler = (DownloadHandler) new
DownloadHandlerBuffer();
request.SetRequestHeader("Content-Type", "application/json");
yield return request.SendWebRequest();
if (request.isHttpError || request.isNetworkError)
{
Debug.Log(request.error);
NotificationHelper.showOnePopup("Error \n"+request.error);
callback(null);
}
else
{
//Debug.Log(request.downloadHandler.text);
string json =
FirebaseSetup.RESTToJsonConverter(request.downloadHandler.text);
callback(json);
}
下面是我的 FirebaseSetup Class
public static string FirebaseToJsonConverter(DataSnapshot snapshot){
string data = "[";
int i = 0;
foreach(DataSnapshot s in snapshot.Children){
data += s.GetRawJsonValue();
i++;
if(i != snapshot.ChildrenCount)
data += ",";
}
data += "]";
string JSONToParse = "{\"values\":" + data + "}";
return JSONToParse;
}
public static string RESTToJsonConverter(string incoming_data)
{
Debug.Log($"incoming_data:/n{incoming_data}");
// remove everything before the SECOND occurrence of '{'
// remove last occurrence of '}'
var startIndex = incoming_data.IndexOf('{', incoming_data.IndexOf('{') + 1);
var endIndex = incoming_data.LastIndexOf('}') - 1;
var json = incoming_data.Substring(startIndex, endIndex - startIndex);
// then remove leading or trailing whitespace
json = json.Trim();
Debug.Log($"json:/n{json}");
var data = JsonUtility.FromJson<string>(json);
return data;
}
尝试@derHugo 代码后,出现新错误。
This is my new error
对于你的具体情况,我会反过来:
根字段名称通常无关紧要,因此如果您删除尾随 }
并从 second {
开始字符串,您将拥有
{
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bob",
"objName": "Bobby",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
}
您可以简单地为
创建一个 c# class
[Serializable]
public class Data
{
public string assetName;
public string id;
public string imageName;
public string name;
public string objName;
public string point;
public string versionNumber;
}
然后你可以使用 JsonUtility
public static Data RESTToJsonConverter(string incoming_data)
{
Debug.Log($"incoming_data:/n{incoming_data}");
// remove everything before the SECOND occurrence of '{'
// remove last occurrence of '}'
var startIndex = incoming_data.IndexOf('{', incoming_data.IndexOf('{') + 1);
var endIndex = incoming_data.LastIndexOf('}') - 1;
var json = incoming_data.Substring(startIndex, endIndex - startIndex);
// then remove leading or trailing whitespace
json = json.Trim();
Debug.Log($"json:/n{json}");
var data = JsonUtility.FromJson<Data>(json);
return data;
}
更新
您现在更新了问题内容,因此现在数据以数据对象字典的形式出现。
在这种情况下,您可以使用 Newtonsoft Json.NET
,它直接支持 Dictionary
的(反)序列化,例如
[Serializable]
public class Data
{
public string assetName;
public string id;
public string imageName;
public string name;
public string objName;
public string point;
public string versionNumber;
}
然后做类似
的事情
public static Dictionary<string, Data> RESTToJsonConverter(string incoming_data)
{
Debug.Log($"incoming_data:/n{incoming_data}");
var data = JsonConvert.DeserializeObject<Dictionary<string, Data>(json);
return data;
}
然后你可以做例如
var datas = RESTToJsonConverter(receivedRawData);
foreach(var data in data.Values)
{
Debug.Log(data.id);
}
我想,您的问题是关于 JSON 和 non-unique 键的反序列化。
如果是,请看这里:How to deserialize JSON with duplicate property names in the same object
对于您的情况,解决方案应包含以下内容:
声明您的合同:
public class Data
{
public string assetName{get;set;}
public string id{get;set;}
public string imageName{get;set;}
public string name{get;set;}
public string objName{get;set;}
public string point{get;set;}
public string versionNumber{get;set;}
}
你的“自定义解串器”:)
public static JToken DeserializeAndCombineDuplicates(JsonTextReader reader)
{
if (reader.TokenType == JsonToken.None)
{
reader.Read();
}
if (reader.TokenType == JsonToken.StartObject)
{
reader.Read();
JObject obj = new JObject();
while (reader.TokenType != JsonToken.EndObject)
{
string propName = (string)reader.Value;
reader.Read();
JToken newValue = DeserializeAndCombineDuplicates(reader);
JToken existingValue = obj[propName];
if (existingValue == null)
{
obj.Add(new JProperty(propName, newValue));
}
else if (existingValue.Type == JTokenType.Array)
{
CombineWithArray((JArray)existingValue, newValue);
}
else // Convert existing non-array property value to an array
{
JProperty prop = (JProperty)existingValue.Parent;
JArray array = new JArray();
prop.Value = array;
array.Add(existingValue);
CombineWithArray(array, newValue);
}
reader.Read();
}
return obj;
}
if (reader.TokenType == JsonToken.StartArray)
{
reader.Read();
JArray array = new JArray();
while (reader.TokenType != JsonToken.EndArray)
{
array.Add(DeserializeAndCombineDuplicates(reader));
reader.Read();
}
return array;
}
return new JValue(reader.Value);
}
private static void CombineWithArray(JArray array, JToken value)
{
if (value.Type == JTokenType.Array)
{
foreach (JToken child in value.Children())
array.Add(child);
}
else
{
array.Add(value);
}
}
获取 Dictionary 作为结果类型的一些代码
using (StringReader sr = new StringReader(json))
using (JsonTextReader reader = new JsonTextReader(sr))
{
var parsed = DeserializeAndCombineDuplicates(reader).ToObject<Dictionary<string, Data[]>>();
if(parsed!=null)
{
parsed
.ToList()
.ForEach(x=>Console.WriteLine("\r\nkey={0}\r\nvalues:\r\n{1}"
, x.Key
, string.Join("\r\n", x.Value
.Select(z=>string.Join("\t\t", z.name, z.id, z.objName))
.ToArray())));
} else Console.WriteLine("No way, dude!");
}
完整的解决方案放在这里:https://dotnetfiddle.net/lYBytk
public static string RESTToJsonConverter(string incoming_data){
string data = "[";
int i = 0;
Debug.Log("incoming_data"+incoming_data);
data += "]";
string JSONToParse = "{\"values\":" + data + "}";
return JSONToParse;
}
下面是我 运行 该代码时的结果。我的问题是如何在不使用 "M4qRmfIqhKdy643Ujye"
密钥(自动生成)的情况下 access/get 所有数据?
如果使用 JavaScript,我可以使用 object.values
但是因为我使用的是 C#,所以我不知道如何获取数据。
{
"-M4qRmfIqhKdy643Ujye": {
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bob",
"objName": "Bobby",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
},
"-M4qRmfIqhKdy643Ujye": {
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bobfds",
"objName": "Bobbydsf",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
},
"-M4qRmfIqhKdy643Ujye": {
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bobfdsa",
"objName": "Bobbyfc",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
}
}
更新
这是我的下载器中的功能之一Class
IEnumerator DownloadData(string dataPath, Action<string> callback){
Debug.Log("dataPath=>"+dataPath);
var token = LocalData.getAuth();
Auth data = JsonUtility.FromJson<Auth>(token);
var request = new
UnityWebRequest("https://test123.firebaseio.com/"+dataPath+".json?
auth="+data.idToken, "GET");
request.downloadHandler = (DownloadHandler) new
DownloadHandlerBuffer();
request.SetRequestHeader("Content-Type", "application/json");
yield return request.SendWebRequest();
if (request.isHttpError || request.isNetworkError)
{
Debug.Log(request.error);
NotificationHelper.showOnePopup("Error \n"+request.error);
callback(null);
}
else
{
//Debug.Log(request.downloadHandler.text);
string json =
FirebaseSetup.RESTToJsonConverter(request.downloadHandler.text);
callback(json);
}
下面是我的 FirebaseSetup Class
public static string FirebaseToJsonConverter(DataSnapshot snapshot){
string data = "[";
int i = 0;
foreach(DataSnapshot s in snapshot.Children){
data += s.GetRawJsonValue();
i++;
if(i != snapshot.ChildrenCount)
data += ",";
}
data += "]";
string JSONToParse = "{\"values\":" + data + "}";
return JSONToParse;
}
public static string RESTToJsonConverter(string incoming_data)
{
Debug.Log($"incoming_data:/n{incoming_data}");
// remove everything before the SECOND occurrence of '{'
// remove last occurrence of '}'
var startIndex = incoming_data.IndexOf('{', incoming_data.IndexOf('{') + 1);
var endIndex = incoming_data.LastIndexOf('}') - 1;
var json = incoming_data.Substring(startIndex, endIndex - startIndex);
// then remove leading or trailing whitespace
json = json.Trim();
Debug.Log($"json:/n{json}");
var data = JsonUtility.FromJson<string>(json);
return data;
}
尝试@derHugo 代码后,出现新错误。
This is my new error
对于你的具体情况,我会反过来:
根字段名称通常无关紧要,因此如果您删除尾随 }
并从 second {
开始字符串,您将拥有
{
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bob",
"objName": "Bobby",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
}
您可以简单地为
创建一个 c# class[Serializable]
public class Data
{
public string assetName;
public string id;
public string imageName;
public string name;
public string objName;
public string point;
public string versionNumber;
}
然后你可以使用 JsonUtility
public static Data RESTToJsonConverter(string incoming_data)
{
Debug.Log($"incoming_data:/n{incoming_data}");
// remove everything before the SECOND occurrence of '{'
// remove last occurrence of '}'
var startIndex = incoming_data.IndexOf('{', incoming_data.IndexOf('{') + 1);
var endIndex = incoming_data.LastIndexOf('}') - 1;
var json = incoming_data.Substring(startIndex, endIndex - startIndex);
// then remove leading or trailing whitespace
json = json.Trim();
Debug.Log($"json:/n{json}");
var data = JsonUtility.FromJson<Data>(json);
return data;
}
更新
您现在更新了问题内容,因此现在数据以数据对象字典的形式出现。
在这种情况下,您可以使用 Newtonsoft Json.NET
,它直接支持 Dictionary
的(反)序列化,例如
[Serializable]
public class Data
{
public string assetName;
public string id;
public string imageName;
public string name;
public string objName;
public string point;
public string versionNumber;
}
然后做类似
的事情public static Dictionary<string, Data> RESTToJsonConverter(string incoming_data)
{
Debug.Log($"incoming_data:/n{incoming_data}");
var data = JsonConvert.DeserializeObject<Dictionary<string, Data>(json);
return data;
}
然后你可以做例如
var datas = RESTToJsonConverter(receivedRawData);
foreach(var data in data.Values)
{
Debug.Log(data.id);
}
我想,您的问题是关于 JSON 和 non-unique 键的反序列化。 如果是,请看这里:How to deserialize JSON with duplicate property names in the same object
对于您的情况,解决方案应包含以下内容:
声明您的合同:
public class Data
{
public string assetName{get;set;}
public string id{get;set;}
public string imageName{get;set;}
public string name{get;set;}
public string objName{get;set;}
public string point{get;set;}
public string versionNumber{get;set;}
}
你的“自定义解串器”:)
public static JToken DeserializeAndCombineDuplicates(JsonTextReader reader)
{
if (reader.TokenType == JsonToken.None)
{
reader.Read();
}
if (reader.TokenType == JsonToken.StartObject)
{
reader.Read();
JObject obj = new JObject();
while (reader.TokenType != JsonToken.EndObject)
{
string propName = (string)reader.Value;
reader.Read();
JToken newValue = DeserializeAndCombineDuplicates(reader);
JToken existingValue = obj[propName];
if (existingValue == null)
{
obj.Add(new JProperty(propName, newValue));
}
else if (existingValue.Type == JTokenType.Array)
{
CombineWithArray((JArray)existingValue, newValue);
}
else // Convert existing non-array property value to an array
{
JProperty prop = (JProperty)existingValue.Parent;
JArray array = new JArray();
prop.Value = array;
array.Add(existingValue);
CombineWithArray(array, newValue);
}
reader.Read();
}
return obj;
}
if (reader.TokenType == JsonToken.StartArray)
{
reader.Read();
JArray array = new JArray();
while (reader.TokenType != JsonToken.EndArray)
{
array.Add(DeserializeAndCombineDuplicates(reader));
reader.Read();
}
return array;
}
return new JValue(reader.Value);
}
private static void CombineWithArray(JArray array, JToken value)
{
if (value.Type == JTokenType.Array)
{
foreach (JToken child in value.Children())
array.Add(child);
}
else
{
array.Add(value);
}
}
获取 Dictionary
using (StringReader sr = new StringReader(json))
using (JsonTextReader reader = new JsonTextReader(sr))
{
var parsed = DeserializeAndCombineDuplicates(reader).ToObject<Dictionary<string, Data[]>>();
if(parsed!=null)
{
parsed
.ToList()
.ForEach(x=>Console.WriteLine("\r\nkey={0}\r\nvalues:\r\n{1}"
, x.Key
, string.Join("\r\n", x.Value
.Select(z=>string.Join("\t\t", z.name, z.id, z.objName))
.ToArray())));
} else Console.WriteLine("No way, dude!");
}
完整的解决方案放在这里:https://dotnetfiddle.net/lYBytk