以年和日计算年龄 PHP

Question

我知道多年来这个问题被问过很多次，但我得到的结果仍然与我认为应该正确的不同。我有以下代码计算两个日期之间的天数，然后将其转换为年和天。当我转换结果不是我所期望的。见下文。请让我知道哪里不正确，这真的很令人沮丧。

谢谢！

$born = '1985-09-09';
$date = date('Y-m-d H:i:s'); // this is today's date
$birthdate = new DateTime("$born");
$today = new DateTime("$date");

$diff = $today->diff($birthdate)->format("%a");

$days = $diff;
$years_remaining = intval($days / 365); //divide by 365 and throw away the remainder
$days_remaining = $days % 365;    

echo "<b>Age:</b> ".$years_remaining."y-".$days_remaining."d<br />";

我想出现的：年龄：35岁-0岁

但我得到的是：年龄: 35y-9d

Answer 1

因为闰年有 366 天，所以不能只除以 days/365:

<?php
$born = '1985-09-05';
$date = date('Y-m-d H:i:s'); // this is today's date
$birthdate = new DateTime("$born");
$today = new DateTime("$date");

// get diff in full years
$diff_years = $today->diff($birthdate)->format("%y");

// add years diff to birthday, (so here your last birthday date)
$birthdate->add(new DateInterval("P{$diff_years}Y"));

// count days since your last birthday party day
$diff_days = $today->diff($birthdate)->format("%a");

echo "Age: ".$diff_years."y and ".$diff_days." days ";

Here you can try live PHP code

以年和日计算年龄 PHP

Calculate age In Years and Days PHP

php

time

date

converters

calculation