Flatlist inside Flatlist : 从 parent Flatlist 获取数据
Flatlist inside Flatlist : get data from the parent Flatlist
我正在渲染多张幻灯片,每张幻灯片都有一个项目列表。
所以我不得不像这样在 Flatlist 中渲染一个 Flatlist:
<FlatList
ref={(list) => this.ref= list}
data={this.state.buttons} // parent data
keyExtractor={(item) => item.id.toString()}
...
getItemLayout={(data, index)=> (
{
length: wp('100%'),
offset: wp('100%') * index,
index,
borderWidth: 1, borderColor: 'red',
}
)}
showsHorizontalScrollIndicator={false}
renderItem={({item}) => {
let parentData = item;
let myData = this.state.listGifts + '.' + parentData.name;
console.warn('data ', parentData, item);
return (
<View style={{width: wp('100%')}}>
{
this.state.isLoading ?
<ActivityIndicator size='large' style={Styles.styleAI} color={Colors.mainYellow}/>
:
<FlatList
contentContainerStyle={Styles.flatContent}
data={myData}
// keyExtractor={(item) => item.id.toString()}
renderItem={this.renderItem}
removeClippedSubviews={true}
extraData={this.state}
/>
}
</View>
)
}
}
extraData={this.state}
/>
我取了两个 JSON :
this.state.buttons >
{
"message": "",
"success": true,
"Category": [
{
"id": 2,
"name": "Peinture"
},
{
"id": 3,
"name": "Cuisine"
},
{
"id": 4,
"name": "Outils"
},
{
"id": 5,
"name": "Electromenager"
}
]
}
this.state.giftsList >
{
"message": "OK",
"success": true,
"Peinture": [
{
"idCadeau": 2,
"Cadeau": "Cadeau1",
"Unites": "100",
},
{
"idCadeau": 3,
"Cadeau": "Cadeau2",
"Unites": "1000",
},
{
"idCadeau": 4,
"Cadeau": "Cadeau3",
"Unites": "50",
}
],
"Cuisine": [
{
"idCadeau": 5,
"Cadeau": "Cadeau4",
"Unites": "200",
},
{
"idCadeau": 6,
"Cadeau": "Cadeau5",
"Unites": "2500",
}
],
"Outils": [
{
"idCadeau": 7,
"Cadeau": "Cadeau6",
"Unites": "100",
}
],
"Electromenager": [
{
"idCadeau": 9,
"Cadeau": "Cadeau7",
"Unites": "500",
}
]
}
对于第二个 Flatlist(child),我尝试获取这样的数据(见下面的代码):
let myData = this.state.listGifts + '.' + parentData.name;
...
data={myData}
但它不起作用!我评论这个 // keyExtractor={(item) => item.idCadeau.toString()}
因为它给出了一个错误然后它给了我一个空列表。
**
我想要的是这样设置数据:
**
data={this.state.listGifts.Peinture}
data={this.state.listGifts.Cuisine}
data={this.state.listGifts.Outils}
...
如果 this.state.listGifts
是一个对象,那么我相信你的意思是做这样的事情:
let myData = this.state.listGifts[parentData.name];
我正在渲染多张幻灯片,每张幻灯片都有一个项目列表。 所以我不得不像这样在 Flatlist 中渲染一个 Flatlist:
<FlatList
ref={(list) => this.ref= list}
data={this.state.buttons} // parent data
keyExtractor={(item) => item.id.toString()}
...
getItemLayout={(data, index)=> (
{
length: wp('100%'),
offset: wp('100%') * index,
index,
borderWidth: 1, borderColor: 'red',
}
)}
showsHorizontalScrollIndicator={false}
renderItem={({item}) => {
let parentData = item;
let myData = this.state.listGifts + '.' + parentData.name;
console.warn('data ', parentData, item);
return (
<View style={{width: wp('100%')}}>
{
this.state.isLoading ?
<ActivityIndicator size='large' style={Styles.styleAI} color={Colors.mainYellow}/>
:
<FlatList
contentContainerStyle={Styles.flatContent}
data={myData}
// keyExtractor={(item) => item.id.toString()}
renderItem={this.renderItem}
removeClippedSubviews={true}
extraData={this.state}
/>
}
</View>
)
}
}
extraData={this.state}
/>
我取了两个 JSON : this.state.buttons >
{
"message": "",
"success": true,
"Category": [
{
"id": 2,
"name": "Peinture"
},
{
"id": 3,
"name": "Cuisine"
},
{
"id": 4,
"name": "Outils"
},
{
"id": 5,
"name": "Electromenager"
}
]
}
this.state.giftsList >
{
"message": "OK",
"success": true,
"Peinture": [
{
"idCadeau": 2,
"Cadeau": "Cadeau1",
"Unites": "100",
},
{
"idCadeau": 3,
"Cadeau": "Cadeau2",
"Unites": "1000",
},
{
"idCadeau": 4,
"Cadeau": "Cadeau3",
"Unites": "50",
}
],
"Cuisine": [
{
"idCadeau": 5,
"Cadeau": "Cadeau4",
"Unites": "200",
},
{
"idCadeau": 6,
"Cadeau": "Cadeau5",
"Unites": "2500",
}
],
"Outils": [
{
"idCadeau": 7,
"Cadeau": "Cadeau6",
"Unites": "100",
}
],
"Electromenager": [
{
"idCadeau": 9,
"Cadeau": "Cadeau7",
"Unites": "500",
}
]
}
对于第二个 Flatlist(child),我尝试获取这样的数据(见下面的代码):
let myData = this.state.listGifts + '.' + parentData.name;
...
data={myData}
但它不起作用!我评论这个 // keyExtractor={(item) => item.idCadeau.toString()}
因为它给出了一个错误然后它给了我一个空列表。
**
我想要的是这样设置数据:
**
data={this.state.listGifts.Peinture}
data={this.state.listGifts.Cuisine}
data={this.state.listGifts.Outils}
...
如果 this.state.listGifts
是一个对象,那么我相信你的意思是做这样的事情:
let myData = this.state.listGifts[parentData.name];