代码 'for' 'in' 'not in' 不工作，如何修复以尊重命令之前给出的答案？

Question

我一直在尝试制作一个简单的小游戏，您可以在其中行走并找到不同的东西，但出于某种原因，当我键入 for 和 in 命令时，它不尊重 b[ 中的答案=20=]

#
print('You may now begin your quest because I said so')
print('You must choose a number between 1 and 10, each number must be selected only once')
a = int(input('How many block do you wanna walk?'))
if a == 1:
    print('Really? 1 block? LUL')
if a == 2:
    b = str(input("You've found a hole, it is too dark too see what's on it though, do you wish to explore?"))
    hang = ("yes")
for b in hang:
    print('You fell and died.')
else:
    print('Ok then, keep going.')

如您所见，它非常简单，但它始终同时显示 for b in hang: 和 else 我确实尝试创建另一个列表 fk = ("no") 并更改 else for for b in fk: print('Ok then, keep going') 但它也不起作用，我也尝试放置 for b not in hang: print('Ok then, keep going') 但梯子根本不起作用

Answer 1

仅通过阅读您的代码，您似乎正在迭代字母 y、e 和 s

你到底想做什么？

如果 hang 应该是元组，请尝试向其添加 ,：

hang = ('yes',) 

if b in hang:
    print('You fell and died.')
else:
    print('Ok then, keep going.')

Answer 2

你可以试试：

if b.startswith('y'):
    print('you fell and died')

代码 'for' 'in' 'not in' 不工作，如何修复以尊重命令之前给出的答案？

Code 'for' 'in' 'not in' not working, how to fix so it respects answers give prior to commands?

python

syntax

list

syntax-error

pycharm