Spring 数据 JPA - 规范

Question

我在将规范传递给 repository.findAll()

时遇到问题

Version:spring-boot-starter-data-jpa-2.2.4.RELEASE

存储库

@Repository
public interface ServerAttributesRepository extends JpaRepository<ServerAttributes, Integer>{
    public ServerAttributes findById(int Id);
}

当我通过传递规范调用 repository.findAll 时，出现错误

ServerAttributeSpecification spec1 = new ServerAttributeSpecification(
            new SearchCriteria("server", SearchOperation.EQUALITY, "1"));
    List<ServerAttributes> serverAttributesList = serverAttributesRepository.findAll(spec1);

错误：

Cannot resolve method 'findAll(com.cloud.compareService.specification.ServerAttributeSpecification)'

我在我的 JpaRepository

中找不到 findAll(Specification<T> spec)

参考：https://www.baeldung.com/rest-api-query-search-language-more-operations

Answer 1

您需要扩展 JpaSpecificationExecutor 接口以获得对规范的支持，因此尝试：

@Repository
public interface ServerAttributesRepository extends JpaRepository<ServerAttributes, Integer>, JpaSpecificationExecutor<ServerAttributes> {
    public ServerAttributes findById(int Id);
}

Spring 数据 JPA - 规范

Spring data JPA - specification

java

spring

spring-data

spring-repositories