简单的电话簿查找 else 函数运行即使 if 语句为真

Question

我正在尝试制作一本简单的 phone 书，如果您输入 1：您将联系人添加到字典中，如果 2 您根据输入的名称（键）查找字典，如果 3 你根据输入的数字(value)查字典

当我运行根据值（输入 3）进行键查找时，它 returns else 函数 'this is invalid' 不管它是否为真。

有人能破译吗？

    #Input contact name
    if button == 1:
        name = input('Please enter the contact name:') 
        if name in contacts:
            print("The name you entered already exists in the address book --> %s:%s"\
            %(name,contacts[name]))
            flag = input("Whether to modify user information (YES/NO):")
            if  flag== 'YES':  
                tel = input('Please enter the users contact phone number:') 
                contacts.update({name:tel}) #Update dictionary
                print("Contacts have been updated!")
            else:
                continue
        else:
            contacts[name] =  input('Please enter the contact phone number:')
            print("Contact has been saved!")
    
    #Search by contact name
    if button == 2:
        name = input('Please enter the contact name:') 
        if name in contacts:
            print("%s : %s "%(name,contacts[name]))
        else:
            print('The name you entered is no longer in the address book! ') 
   
            
   #Search by contact number
    if button == 3:
        numba = input('Please enter the contact number:') 
        lookup = []
        for key,value in contacts.items():
            if(value == numba):
                lookup.append(key)
                print('Name(s) matching number is',lookup)
            else:
                print('This is invalid')

Answer 1

试试这个：

if button == 3:
    numba = input('Please enter the contact number:') 
    lookup = []
    for key,value in contacts.items():
        if(value == numba):
            lookup.append(key)
    if lookup: # True if len(lookup) != 0
        print('Name(s) matching number is', lookup)
    else:
        print('This is invalid')

Answer 2

可能有点牵强，但我是这样工作的：

numba = input('Please enter the contact number: ')
lookup = []
for key,value in contacts.items():
    if(numba == key):
        lookup.append(value)
        print('Name(s) matching number is', lookup)

if(int(numba) > len(contacts.items())):
    print('This is invalid')

简单的电话簿查找 else 函数运行即使 if 语句为真

Simple phonebook lookup else function running even when if statement is true

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dictionary

key-value

python-3.x

简单的电话簿查找 else 函数 运行 即使 if 语句为真

Simple phonebook lookup else function running even when if statement is true

python

dictionary

key-value

python-3.x

简单的电话簿查找 else 函数运行即使 if 语句为真