我的 Gmail 无法获取 Google Apps 脚本 运行

Question

我遵循了 Any way to send Gmail auto-response at certain times every week? 中发布的脚本。但是，根据我当前的测试，我的 Gmail 帐户在非工作时间没有回复任何邮件。

我做错了什么或不完整吗？

我做了什么：

1. 通过复制和粘贴在 https://script.google.com/ 上创建了一个脚本。
2. 保存脚本并进行测试。它运作良好。 enter image description here

function myFunction() {
  function autoReply() {
var interval = 5;    //  if the script runs every 5 minutes; change otherwise
  var date = new Date();
  var day = date.getDay();
  var hour = date.getHours();
  if ([4,5,6,0].indexOf(day) > -1 || (day == 1 && hour < 9) || (day == 3 && hour >= 17)) {
    var timeFrom = Math.floor(date.valueOf()/1000) - 60 * interval;
    var threads = GmailApp.search('is:inbox after:' + timeFrom);
    for (var i = 0; i < threads.length; i++) {
      if (threads[i].isUnread()){
      threads[i].reply("xxxx");
      threads[i].markRead();
      threads[i].markImportant();
      }
    }
  }
}
}

3. 通过菜单“高级 Google 服务”启用 Gmail API enter image description here
4. 将脚本设置为每 5 分钟触发一次。 enter image description here
5. 从另一个 Gmail 帐户发送了几封测试电子邮件，看看是否会有任何自动回复。
6. 没有手动修改任何从其他帐户收到的电子邮件。

任何提示将不胜感激！

更新：我想知道为什么下面的脚本本身会导致“找不到脚本函数：myFunction”错误？

function autoReply() {
  
  // find calendar event
  var today = new Date();
  var events = CalendarApp.getDefaultCalendar().getEventsForDay(today, { search: 'OOF' });
  var unavailableToday = false;
  for (var i = 0; i < events.length; i++) {
    
    if(events[i].isAllDayEvent() && events[i].isOwnedByMe()) {
      
      unavailableToday = true;
      break;
      
    }
    
  }
  
  var myEmail = Session.getEffectiveUser().getEmail();
  
  Logger.log('unavailableToday');
  Logger.log(unavailableToday);
  if(unavailableToday === true) {
    
    // get html message
    var files = DriveApp.getRootFolder().getFilesByName('autoreply.html');
    var htmlbody;
    while (files.hasNext()) {
      var file = files.next();

      htmlbody = file.getBlob().getDataAsString('utf8');
      
    }
   
    // get emails
    var interval = 2;
    var date = new Date();
    var timeFrom = Math.floor(date.valueOf()/1000) - 60 * interval;
    var threads = GmailApp.search('is:inbox !label:autoresponded after:' + timeFrom);
    var label = GmailApp.getUserLabelByName("autoresponded");

    for (var i = 0; i < threads.length; i++) {
      
      var message = threads[i].getMessages()[0];
      if (message.getFrom().indexOf(myEmail) < 0 && message.getFrom().indexOf("no-repl") < 0 && message.getFrom().indexOf("bounce") < 0 && message.getFrom().indexOf("spam") < 0) {
        
        Logger.log("Replied now");
        
        // reply
        threads[i].reply("", {
          htmlBody: htmlbody
        });
        
        // label
        label.addToThread(threads[i]);
        
      }
      
    }
    
  }
  
}

是什么让我觉得 MyFunction{} 必不可少？

Answer 1

答案：

您需要删除 myFunction() 之外的 autoReply() 函数并在 autoReply() 上设置触发器。

更多信息：

代码应该与您链接的答案中的代码类似：

function autoReply() {
  var interval = 5;    //  if the script runs every 5 minutes; change otherwise
  var date = new Date();
  var day = date.getDay();
  var hour = date.getHours();
  if ([5,6,0].indexOf(day) > -1 || (day == 1 && hour < 8) || (day == 4 && hour >= 17)) {
    var timeFrom = Math.floor(date.valueOf()/1000) - 60 * interval;
    var threads = GmailApp.search('is:inbox after:' + timeFrom);
    for (var i = 0; i < threads.length; i++) {
      threads[i].reply("I am out of office. Your email will not seen until Monday morning.");
    }
  }
}

不是这样的：

function myFunction() {
  function autoReply() {
    var interval = 5;    //  if the script runs every 5 minutes; change otherwise
    var date = new Date();
    var day = date.getDay();
    var hour = date.getHours();
    if ([5,6,0].indexOf(day) > -1 || (day == 1 && hour < 8) || (day == 4 && hour >= 17)) {
      var timeFrom = Math.floor(date.valueOf()/1000) - 60 * interval;
      var threads = GmailApp.search('is:inbox after:' + timeFrom);
      for (var i = 0; i < threads.length; i++) {
        threads[i].reply("I am out of office. Your email will not seen until Monday morning.");
      }
    }
  }
}

autoReply() 在您调用 myFunction() 时未被调用，仅被声明。

您需要编辑代码，然后 re-set 在 autoReply() 上将触发器设置为 运行。

来自w3schools：

Declared functions are not executed immediately. They are "saved for later use", and will be executed later, when they are invoked (called upon).

参考文献：

• JavaScript Function Definitions - w3schools