如何在连续出现时合并 'listBulleted' 元素

Question

元素 'listBulleted' 具有相同的父元素，这里我们试图仅合并那些具有 conscutive/countinued 的 'listBulleted' 元素，否则保持原样：

注意：我们正在创建特定的“”模板，以便我们可以在其他 xslt 中轻松 moved/add。

输入XML:

<?xml version="1.0" encoding="UTF-8"?>
<root>
<listBulleted>
    <listItem><para flow="new"><emphasis bold="yes">Design.</emphasis> Approval of the specific design of the tiebacks or underpinning.</para>
        <listBulleted>
            <listItem><para flow="new">The location of the tiebacks.</para></listItem>
            <listItem><para flow="new">The design of underpinning will be critical.</para></listItem>
        </listBulleted></listItem>
    <listItem><para flow="new"><emphasis bold="yes">Design Professionals and Contractors.</emphasis>.</para></listItem>
</listBulleted>
<listBulleted>
    <listItem><para flow="new"><emphasis bold="yes">Means of Installation.</emphasis> Approval of the timing.</para></listItem>
</listBulleted>
<listBulleted>
    <listItem><para flow="new"><emphasis bold="yes">Liability for Damages.</emphasis> The constructing party’s.</para></listItem>
</listBulleted>
<listBulleted>
    <listItem><para flow="new"><emphasis bold="yes">Adjacent Property Owner’s Rights</emphasis></para>
        <listBulleted>
            <listItem><para flow="new">An acknowledgment by the constructing party.</para></listItem>
            <listItem><para flow="new">Assurances for the constructing party.</para></listItem>
            <listItem><para flow="new">The assurances described in the preceding recorded.</para></listItem>
        </listBulleted></listItem>
</listBulleted>
<listBulleted>
    <listItem><para flow="new"><emphasis bold="yes">Insurance.</emphasis> Description.</para></listItem>
</listBulleted>
</root>

预期输出：

<?xml version="1.0" encoding="UTF-8"?>
<root>
<listBulleted>
    <listItem><para flow="new"><emphasis bold="yes">Design.</emphasis> Approval of the specific design of the tiebacks or underpinning.</para>
        <listBulleted>
            <listItem><para flow="new">The location of the tiebacks.</para></listItem>
            <listItem><para flow="new">The design of underpinning will be critical.</para></listItem>
        </listBulleted></listItem>
    <listItem><para flow="new"><emphasis bold="yes">Design Professionals and Contractors.</emphasis>.</para></listItem>
    <listItem><para flow="new"><emphasis bold="yes">Means of Installation.</emphasis> Approval of the timing.</para></listItem>
    <listItem><para flow="new"><emphasis bold="yes">Liability for Damages.</emphasis> The constructing party’s.</para></listItem>
    <listItem><para flow="new"><emphasis bold="yes">Adjacent Property Owner’s Rights</emphasis></para>
        <listBulleted>
            <listItem><para flow="new">An acknowledgment by the constructing party.</para></listItem>
            <listItem><para flow="new">Assurances for the constructing party.</para></listItem>
            <listItem><para flow="new">The assurances described in the preceding recorded.</para></listItem>
        </listBulleted></listItem>
    <listItem><para flow="new"><emphasis bold="yes">Insurance.</emphasis> Description.</para></listItem>
</listBulleted>
</root>

XSLT 代码：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">

<xsl:template match="node()|@*">
    <xsl:copy>
        <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="listBulleted">
    <listBulleted>
        <xsl:apply-templates select="@*"/>
        <xsl:apply-templates/>
        <xsl:if test="following-sibling::node()[1][self::listBulleted]">
            <xsl:apply-templates select="following-sibling::node()[1][self::listBulleted]/node()"/>
        </xsl:if>
    </listBulleted>
</xsl:template>
<xsl:template match="listBulleted[preceding-sibling::node()[1][self::listBulleted]]"/>

</xsl:stylesheet>

参考URL:https://xsltfiddle.liberty-development.net/6q1S8Az/1

Answer 1

教科书方法是group-adjacent:

<xsl:template match="*[listBulleted]">
    <xsl:copy>
        <xsl:for-each-group select="*" group-adjacent=". instance of element(listBulleted)">
            <xsl:choose>
                <xsl:when test="current-grouping-key()">
                    <xsl:copy>
                        <xsl:apply-templates select="current-group()/node()"/>
                    </xsl:copy>
                </xsl:when>
                <xsl:otherwise>
                    <xsl:apply-templates select="current-group()"/>
                </xsl:otherwise>
            </xsl:choose>
        </xsl:for-each-group>
    </xsl:copy>
</xsl:template>

https://xsltfiddle.liberty-development.net/6q1S8Az/2

它与 listBulleted 不匹配，因为那不是您需要分组的容器。

如何在连续出现时合并 'listBulleted' 元素

HOW TO MEARGE THE 'listBulleted' ELEMENT WHILE COMING CONSCUTVELY

xml

xpath

xquery

xslt-2.0