CI 上出现“解析错误”的 PHPunit 测试错误

Question

我正在 phpunit 9.3.8 的帮助下对我的代码进行单元测试。测试运行在我的本地开发环境中很好（我是运行ning Windows 10，PHP 7.4.2 和 Xdebug 2.9.2）但是由于解析错误而失败我尝试在 Gitlab CI 上运行 phpunit（CI 运行是最新的 alpine linux 图像）。

错误是：

$ composer run test
> phpunit
PHPUnit 9.3.8 by Sebastian Bergmann and contributors.
Runtime:       PHP 7.3.23 with Xdebug 2.9.8
Configuration: /builds/gaspacchio/back-to-the-future/phpunit.xml
Reporter
 ✘ Can set short message [6.05 ms]
   │
   │ ParseError: syntax error, unexpected 'int' (T_STRING), expecting function (T_FUNCTION) or const (T_CONST)
   │
   │ /builds/gaspacchio/back-to-the-future/src/api/utilities/Reporter.php:21
   │ /builds/gaspacchio/back-to-the-future/src/api/tests/ReporterTest.php:12
   │

// More errors

Time: 00:01.970, Memory: 310.00 MB
ERRORS!
Tests: 6, Assertions: 0, Errors: 6.
Generating code coverage report in Clover XML format ... done [00:00.330]
PHP Warning:  fopen(/builds/gaspacchio/back-to-the-future/): failed to open stream: Is a directory in /builds/gaspacchio/back-to-the-future/vendor/phpunit/phpunit/src/Util/Printer.php on line 89
PHP Stack trace:
PHP   1. {main}() /builds/gaspacchio/back-to-the-future/vendor/phpunit/phpunit/phpunit:0
PHP   2. PHPUnit\TextUI\Command::main() /builds/gaspacchio/back-to-the-future/vendor/phpunit/phpunit/phpunit:61
PHP   3. PHPUnit\TextUI\Command->run() /builds/gaspacchio/back-to-the-future/vendor/phpunit/phpunit/src/TextUI/Command.php:100
PHP   4. PHPUnit\TextUI\TestRunner->run() /builds/gaspacchio/back-to-the-future/vendor/phpunit/phpunit/src/TextUI/Command.php:147
PHP   5. PHPUnit\Util\Printer->__construct() /builds/gaspacchio/back-to-the-future/vendor/phpunit/phpunit/src/TextUI/TestRunner.php:756
PHP   6. fopen() /builds/gaspacchio/back-to-the-future/vendor/phpunit/phpunit/src/Util/Printer.php:89
Code Coverage Report:    
  2020-10-13 10:12:09    
                         
 Summary:                
  Classes:  0.00% (0/11) 
  Methods:  0.00% (0/38) 
  Paths:    0.00% (0/7)  
  Branches:    0.00% (0/7)
  Lines:    0.00% (0/397)
Script phpunit handling the test event returned with error code 2

Reporter.php 文件的第 21 行如下：

<?php namespace utilities\Reporter;

/**
 * The Reporter class is responsible for returning data to the client.
 */
class Reporter
{
    /** This is the code of the answer.
     * (more comments)
     * @var int The status code.
     */
    private int $code; //<-- This is line number 21

而ReporterTest.php的第12行是：

<?php

use PHPUnit\Framework\TestCase;
use utilities\Reporter\Reporter;

class ReporterTest extends TestCase
{
    protected $reporter;

    protected function setUp(): void
    {
        $this->reporter = new Reporter(); // <-- Line 12 is here
    }
}

我正在使用 PHPunit 的 fixtures 函数，定义为：

PHPUnit supports sharing the setup code. Before a test method is run, a template method called setUp() is invoked. setUp() is where you create the objects against which you will test.

Answer 1

对象属性的类型提示在 PHP 7.4 中，这是运行

PHPUnit 9.3.8 by Sebastian Bergmann and contributors.

Runtime: PHP 7.3.23 with Xdebug 2.9.8

Answer 2

基本上是PHP版本冲突，出于某种原因，PHPUnit 试图像旧的 PHP 版本一样解析它，其中 private int $code; 无效（应该使用 private $code;）。

哦，刚注意到你的 Windows 系统是运行 PHP 7.4 但是 Gitlab CI 图像已安装 PHP 7.3.23！

CI 上出现“解析错误”的 PHPunit 测试错误

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