使 tkinter 网格交错

Question

我在这里使用这个 grid.py 着色程序 https://scipython.com/blog/a-simple-colouring-grid/ 制作网格的相关代码是

self.cells = []
    for iy in range(n):
        for ix in range(n):
            xpad, ypad = pad * (ix+1), pad * (iy+1)
            x, y = xpad + ix*xsize, ypad + iy*ysize
            rect = self.w.create_rectangle(x, y, x+xsize,
                                       y+ysize, fill=UNFILLED)
            self.cells.append(rect)

我想知道我是否可以得到它，所以方块错开如下所示：

Answer 1

您可以 add/subtract 给定行上单元格的每个 x 坐标的“交错偏移”。由 'row' 的排名确定的值的符号通过将偏移量乘以 (-1)**row.

也许是这样的？:

    self.cells = []
    for row in range(n):
        stagger_offset = (xsize // 4) * (-1)**row   # will be positive for even rows, negative otherwise
        y0 = pad * (row + 1) + row * ysize
        y1 = y0 + ysize
        for col in range(n):
            x0 = pad * (col + 1) + col * xsize + stagger_offset
            x1 = x0 + xsize
            self.cells.append(self.w.create_rectangle(x0, y0, x1, y1, fill=UNFILLED))

您可能需要在 even/odd 行的 beginning/end 处插入半电池，具体取决于您喜欢的视觉效果。

使 tkinter 网格交错

Make a tkinter grid staggered

python

grid

tkinter

tkinter-canvas