查找每组出现次数最多的条目
Finding the entry with the most occurrences per group
我有以下(简化的)架构。
CREATE TABLE TEST_Appointment(
Appointment_id INT AUTO_INCREMENT PRIMARY KEY,
Property_No INT NOT NULL,
Property_Type varchar(10) NOT NULL
);
INSERT INTO TEST_Appointment(Property_No, Property_Type) VALUES
(1, 'House'),
(1, 'House'),
(1, 'House'),
(2, 'Flat'),
(2, 'Flat'),
(3, 'Flat'),
(4, 'House'),
(5, 'House'),
(6, 'Studio');
我正在尝试编写查询以获取每个 属性 类型组中预约次数最多的属性。示例输出为:
Property_No | Property_Type | Number of Appointments
-----------------------------------------------------
1 | House | 3
2 | Flat | 2
6 | Studio | 1
我有以下查询来获取每个 属性 的约会数量,但我不确定如何从那里开始
SELECT Property_No, Property_Type, COUNT(*)
from TEST_Appointment
GROUP BY Property_Type, Property_No;
如果你是运行MySQL8.0,可以使用聚合和window函数:
select *
from (
select property_no, property_type, count(*) no_appointments,
rank() over(partition by property_type order by count(*) desc) rn
from test_appointment
group by property_no, property_type
) t
where rn = 1
在早期版本中,一个选项使用 having
子句和 row-limiting 相关子查询:
select property_no, property_type, count(*) no_appointments
from test_appointment t
group by property_no, property_type
having count(*) = (
select count(*)
from test_appointment t1
where t1.property_type = t.property_type
group by t1.property_no
order by count(*) desc
limit 1
)
请注意,如果有的话,两个查询都允许联系。
我有以下(简化的)架构。
CREATE TABLE TEST_Appointment(
Appointment_id INT AUTO_INCREMENT PRIMARY KEY,
Property_No INT NOT NULL,
Property_Type varchar(10) NOT NULL
);
INSERT INTO TEST_Appointment(Property_No, Property_Type) VALUES
(1, 'House'),
(1, 'House'),
(1, 'House'),
(2, 'Flat'),
(2, 'Flat'),
(3, 'Flat'),
(4, 'House'),
(5, 'House'),
(6, 'Studio');
我正在尝试编写查询以获取每个 属性 类型组中预约次数最多的属性。示例输出为:
Property_No | Property_Type | Number of Appointments
-----------------------------------------------------
1 | House | 3
2 | Flat | 2
6 | Studio | 1
我有以下查询来获取每个 属性 的约会数量,但我不确定如何从那里开始
SELECT Property_No, Property_Type, COUNT(*)
from TEST_Appointment
GROUP BY Property_Type, Property_No;
如果你是运行MySQL8.0,可以使用聚合和window函数:
select *
from (
select property_no, property_type, count(*) no_appointments,
rank() over(partition by property_type order by count(*) desc) rn
from test_appointment
group by property_no, property_type
) t
where rn = 1
在早期版本中,一个选项使用 having
子句和 row-limiting 相关子查询:
select property_no, property_type, count(*) no_appointments
from test_appointment t
group by property_no, property_type
having count(*) = (
select count(*)
from test_appointment t1
where t1.property_type = t.property_type
group by t1.property_no
order by count(*) desc
limit 1
)
请注意,如果有的话,两个查询都允许联系。