Python 字母猜谜游戏

Question

我想制作刽子手 python 游戏，所以我制作了一个更简单的游戏片段。游戏的想法是猜测随机生成的单词中的字母。这是我到目前为止所拥有的。我在底部列出了我遇到的问题。

import random


words = ['holiday', 'american', 'restaurant', 'computer', 'highschool', 'programming']
random_word = random.choice(words)
count = 0


while True:                                     #repeatedly asks you to guess the letter in a random word
    guess = str(input("Guess a letter:  "))
    guess = guess.lower()


    if guess in random_word:             #checks if the letter you input is in the random generated word
        print("Yay, its in the word")
      
    
    else:                          
        count += 1
        print("Not in the word, attempts: %d" % count)
        
        if count > 5:                   
            print("You have reached max attempts")
            print("Sorry, but hangman died! You lose")
            break
        else:
            continue

我遇到的问题：当用户猜一个字母时，他们可以无限次地再次猜它。怎样才能让用户不能重复猜同一个字母？

有没有办法确保用户不会猜出同一个字母？当有几个相同的字母时，这在实际的刽子手游戏中可能会出现问题。任何 help/feedback 感谢，谢谢！

Answer 1

这是一种方法。

import random


words = ['holiday', 'american', 'restaurant', 'computer', 'highschool', 'programming']
random_word = random.choice(words)
count = 0
guess_list = []

while True:                                     #repeatedly asks you to guess the letter in a random word
    guess = str(input("Guess a letter:  "))
    guess = guess.lower()

    if guess not in guess_list:
        if guess in random_word:             #checks if the letter you input is in the random generated word
            print("Yay, its in the word")

        else:                          
            count += 1
            print("Not in the word, attempts: %d" % count)

            if count > 5:                   
                print("You have reached max attempts")
                print("Sorry, but hangman died! You lose")
                break
                
    else:
        print("You have already guessed {}. Try again".format(guess))
        print(set(guess_list))
        
    guess_list.append(guess)

示例输出（word 是计算机）：

Guess a letter:  c
Yay, its in the word
Guess a letter:  e
Yay, its in the word
Guess a letter:  e
You have already guessed e. Try again
{'e', 'c'}
Guess a letter:  e
You have already guessed e. Try again
{'e', 'c'}
Guess a letter:  w
Not in the word, attempts: 1
Guess a letter:  m
Yay, its in the word
Guess a letter:  m
You have already guessed m. Try again
{'w', 'm', 'e', 'c'}
Guess a letter:

备注：

创建一个 guess_list 来记录所有的猜测。
每次猜测后，字母都会附加到列表中。
当用户重复猜测时，他们会收到警告。我们使用集合，因此仅显示猜测列表中的唯一元素。

代码可以进一步细化，但必须完成工作。

Answer 2

根据单词的不同，如果字母出现不止一次，您可能需要允许多次猜测。（这可能不是你的要求，对游戏不熟悉。）

方法

您需要的是一个可以跟踪单词中每个字母出现次数的存储。

类似于：

letterCounts = Counter("hello") # word: 'hello' => {'h': 1, 'e': 1, 'l': 2, 'o': 1}

我在这里使用 counter 集合。

然后可以将猜中字母的次数减1

if guesses_letter in list(letterCounts.elements()):
    if (letterCounts[guessed_letter] > 0):
        letterCounts[guessed_letter] -= 1
    else:
        # the letter can't be repeated now.  do the needful here.

Python 字母猜谜游戏

Python letter guess game

python

counter

if-statement

while-loop

方法