@ManyToMany 注释 spring 使用额外的列和复合键启动 JPA,插入时出错
@ManyToMany annotation spring boot JPA with extra column and composite key ,Error inserting
我正在使用 spring boot 2.2.5 和 Jpa 和 JDK 11,对于我的数据库,我正在使用 oracle 19c。
我的实体用户和组之间存在多对多关系。
在我的 oracle 数据库中,我有一个关联的 (USER_GROUP) table 和复合键 (user_ID,group_ID)。
USER_ID 和 GROUP_ID 是在数据库中自动生成的。
我想当我在 table USER JPA 中插入一个用户时也插入关联的 table USER_GROUP。
但是它 return 总是不能在 USER_ID 中插入 null,而且这个用户 ID 我没有访问权限,因为它是在数据库中自动生成的。
MyClass 用户组:
@Entity
@Table(name = "USER_GROUP", schema = "TEST", catalog = "")
public class UserGroup {
private GroupUserPK groupUserPK;
private User user;
private Group group;
@EmbeddedId
public GroupUserPK getGroupUserPK() {
return groupUserPK;
}
public void setGroupUserPK(GroupUserPK groupUserPK) {
this.groupUserPK = groupUserPK;
}
@JoinColumn(name = "FK_USER_ID")
@MapsId("fkUserId")
@ManyToOne(fetch = FetchType.LAZY)
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
@JoinColumn(name = "FK_GROUP_ID")
@MapsId("fkGroupId")
@ManyToOne(fetch = FetchType.LAZY)
public Group getGroup() {
return group;
}
}
用户组PK
@Embeddable
public class GroupUserPK implements Serializable {
private static final long serialVersionUID = 1L;
private long fkUserId;
private long fkGroupId;
@Column(name = "FK_USER_ID")
@Id
public long getFkUserId() {
return fkUserId;
}
public void setFkUserId(long fkUserId) {
this.fkUserId = fkUserId;
}
@Column(name = "FK_GROUP_ID")
@Id
public long getFkGroupId() {
return fkGroupId;
}
public void setFkGroupId(long fkGroupId) {
this.fkGroupId = fkGroupId;
}
}
MyClass 组:
@Entity
@Table(name = "GROUP", schema = "TEST", catalog = "")
public class Group {
private long groupId;
private String nom;
private Collection<UserGroup> userGroup;
@Id
@Column(name = "GROUP_ID")
public long getGroupId() {
return groupId;
}
public void setGroupId(long groupId) {
this.groupId = groupId;
}
@Basic
@Column(name = "DESIGN")
public String getDesign() {
return design;
}
public void setDesign(String design) {
this.design = design;
}
@OneToMany(mappedBy = "group",cascade = {CascadeType.ALL})
public Collection<UserGroup> getUserGroup() {
return userGroup;
}
public void setUserGroup(Collection<UserGroup> userGroup) {
this.userGroup = userGroup;
}
}
MyClass 用户
@Entity
@Table(name = "USER", schema = "TEST", catalog = "")
public class User {
private long userId;
private String nom;
private Collection<UserGroup> userGroup;
@Id
@Column(name = "USER_ID")
public long getUserId() {
return userId;
}
public void setUserId(long userId) {
this.userId = userId;
}
@Basic
@Column(name = "DESIGN")
public String getDesign() {
return design;
}
public void setDesign(String design) {
this.design = design;
}
@OneToMany(mappedBy = "user",cascade = {CascadeType.ALL})
public Collection<UserGroup> getUserGroup() {
return userGroup;
}
public void setUserGroup(Collection<UserGroup> userGroup) {
this.userGroup = userGroup;
}
}
请帮忙。
编辑
我通过在我的实体用户中添加“addGroup”方法解决了这个问题。
我的实体用户更新为,
@Entity
@Table(name = "USER", schema = "TEST", catalog = "")
public class User {
private long userId;
private String nom;
private Collection<UserGroup> userGroups;
@Id
@Column(name = "USER_ID")
public long getUserId() {
return userId;
}
public void setUserId(long userId) {
this.userId = userId;
}
@Basic
@Column(name = "DESIGN")
public String getDesign() {
return design;
}
public void setDesign(String design) {
this.design = design;
}
@OneToMany(mappedBy = "user", cascade = {CascadeType.ALL})
public Collection<UserGroup> getUserGroups() {
return userGroups;
}
public void setUserGroup(Collection<UserGroup> userGroups) {
this.userGroups = userGroups;
}
public void addGroup(Group group) {
UserGroup userGroup = new UserGroup(this, group);
userGroups.add(userGroup);
group.getUserGroups().add(userGroup);
}
}
之后我们在UserService中调用了这个方法
我正在使用 spring boot 2.2.5 和 Jpa 和 JDK 11,对于我的数据库,我正在使用 oracle 19c。 我的实体用户和组之间存在多对多关系。 在我的 oracle 数据库中,我有一个关联的 (USER_GROUP) table 和复合键 (user_ID,group_ID)。 USER_ID 和 GROUP_ID 是在数据库中自动生成的。 我想当我在 table USER JPA 中插入一个用户时也插入关联的 table USER_GROUP。 但是它 return 总是不能在 USER_ID 中插入 null,而且这个用户 ID 我没有访问权限,因为它是在数据库中自动生成的。
MyClass 用户组:
@Entity
@Table(name = "USER_GROUP", schema = "TEST", catalog = "")
public class UserGroup {
private GroupUserPK groupUserPK;
private User user;
private Group group;
@EmbeddedId
public GroupUserPK getGroupUserPK() {
return groupUserPK;
}
public void setGroupUserPK(GroupUserPK groupUserPK) {
this.groupUserPK = groupUserPK;
}
@JoinColumn(name = "FK_USER_ID")
@MapsId("fkUserId")
@ManyToOne(fetch = FetchType.LAZY)
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
@JoinColumn(name = "FK_GROUP_ID")
@MapsId("fkGroupId")
@ManyToOne(fetch = FetchType.LAZY)
public Group getGroup() {
return group;
}
}
用户组PK
@Embeddable
public class GroupUserPK implements Serializable {
private static final long serialVersionUID = 1L;
private long fkUserId;
private long fkGroupId;
@Column(name = "FK_USER_ID")
@Id
public long getFkUserId() {
return fkUserId;
}
public void setFkUserId(long fkUserId) {
this.fkUserId = fkUserId;
}
@Column(name = "FK_GROUP_ID")
@Id
public long getFkGroupId() {
return fkGroupId;
}
public void setFkGroupId(long fkGroupId) {
this.fkGroupId = fkGroupId;
}
}
MyClass 组:
@Entity
@Table(name = "GROUP", schema = "TEST", catalog = "")
public class Group {
private long groupId;
private String nom;
private Collection<UserGroup> userGroup;
@Id
@Column(name = "GROUP_ID")
public long getGroupId() {
return groupId;
}
public void setGroupId(long groupId) {
this.groupId = groupId;
}
@Basic
@Column(name = "DESIGN")
public String getDesign() {
return design;
}
public void setDesign(String design) {
this.design = design;
}
@OneToMany(mappedBy = "group",cascade = {CascadeType.ALL})
public Collection<UserGroup> getUserGroup() {
return userGroup;
}
public void setUserGroup(Collection<UserGroup> userGroup) {
this.userGroup = userGroup;
}
}
MyClass 用户
@Entity
@Table(name = "USER", schema = "TEST", catalog = "")
public class User {
private long userId;
private String nom;
private Collection<UserGroup> userGroup;
@Id
@Column(name = "USER_ID")
public long getUserId() {
return userId;
}
public void setUserId(long userId) {
this.userId = userId;
}
@Basic
@Column(name = "DESIGN")
public String getDesign() {
return design;
}
public void setDesign(String design) {
this.design = design;
}
@OneToMany(mappedBy = "user",cascade = {CascadeType.ALL})
public Collection<UserGroup> getUserGroup() {
return userGroup;
}
public void setUserGroup(Collection<UserGroup> userGroup) {
this.userGroup = userGroup;
}
}
请帮忙。
编辑
我通过在我的实体用户中添加“addGroup”方法解决了这个问题。
我的实体用户更新为,
@Entity
@Table(name = "USER", schema = "TEST", catalog = "")
public class User {
private long userId;
private String nom;
private Collection<UserGroup> userGroups;
@Id
@Column(name = "USER_ID")
public long getUserId() {
return userId;
}
public void setUserId(long userId) {
this.userId = userId;
}
@Basic
@Column(name = "DESIGN")
public String getDesign() {
return design;
}
public void setDesign(String design) {
this.design = design;
}
@OneToMany(mappedBy = "user", cascade = {CascadeType.ALL})
public Collection<UserGroup> getUserGroups() {
return userGroups;
}
public void setUserGroup(Collection<UserGroup> userGroups) {
this.userGroups = userGroups;
}
public void addGroup(Group group) {
UserGroup userGroup = new UserGroup(this, group);
userGroups.add(userGroup);
group.getUserGroups().add(userGroup);
}
}
之后我们在UserService中调用了这个方法