如何更改我们从 youtube-search-python 包中获得的结果?
How to alter the results we get from the youtube-search-python package?
我正在使用 youtube-search-python 1.3.1 模块来搜索有关特定 youtube 视频的详细信息。
这是它的 PyPi 页面的 link:https://pypi.org/project/youtube-search-python/
我的代码:
from youtubesearchpython import SearchVideos
search = SearchVideos("Video", offset = 1, mode = "json", max_results = 1)
print(search.result())
但是,这样做时,它会打印视频的所有详细信息(属性),如下所示:
{
"search_result": [
{
"index": 0,
"id": "-_4GW6BNIqs",
"link": "https://www.youtube.com/watch?v=-_4GW6BNIqs",
"title": "Insideeus - Ecstasy (Official Video)",
"channel": "InsideeusVEVO",
"duration": "3:27",
"views": 299442272,
"thumbnails": [
"https://img.youtube.com/vi/-_4GW6BNIqs/default.jpg",
"https://img.youtube.com/vi/-_4GW6BNIqs/hqdefault.jpg",
"https://img.youtube.com/vi/-_4GW6BNIqs/mqdefault.jpg",
"https://img.youtube.com/vi/-_4GW6BNIqs/sddefault.jpg",
"https://img.youtube.com/vi/-_4GW6BNIqs/maxresdefault.jpg"
],
"channelId": "UCRNE_wppvoMBdj7EAtUnEog"
}
]
}
我只想打印此结果的“link”部分。我试了很多次都无法得到这个。
有谁知道如何修改代码以便只打印“link”?
这是一个字典,您可以通过
等方式访问值
r = search.result()
for d in r['search_result']:
print(d['link'])
没关系,我找到了答案。
import json
from youtubesearchpython import SearchVideos
search = SearchVideos("Video", offset = 1, mode = "json", max_results = 1)
r = search.result()
res = json.loads(r)
res1 = res['search_result']
res2 = res1[0]
res_fin = res2['link']
print(res_fin)
如果您想要更高级的功能,可以使用searchtube。它还为您提供过滤器选项。
pip install searchtube
我正在使用 youtube-search-python 1.3.1 模块来搜索有关特定 youtube 视频的详细信息。
这是它的 PyPi 页面的 link:https://pypi.org/project/youtube-search-python/
我的代码:
from youtubesearchpython import SearchVideos
search = SearchVideos("Video", offset = 1, mode = "json", max_results = 1)
print(search.result())
但是,这样做时,它会打印视频的所有详细信息(属性),如下所示:
{
"search_result": [
{
"index": 0,
"id": "-_4GW6BNIqs",
"link": "https://www.youtube.com/watch?v=-_4GW6BNIqs",
"title": "Insideeus - Ecstasy (Official Video)",
"channel": "InsideeusVEVO",
"duration": "3:27",
"views": 299442272,
"thumbnails": [
"https://img.youtube.com/vi/-_4GW6BNIqs/default.jpg",
"https://img.youtube.com/vi/-_4GW6BNIqs/hqdefault.jpg",
"https://img.youtube.com/vi/-_4GW6BNIqs/mqdefault.jpg",
"https://img.youtube.com/vi/-_4GW6BNIqs/sddefault.jpg",
"https://img.youtube.com/vi/-_4GW6BNIqs/maxresdefault.jpg"
],
"channelId": "UCRNE_wppvoMBdj7EAtUnEog"
}
]
}
我只想打印此结果的“link”部分。我试了很多次都无法得到这个。
有谁知道如何修改代码以便只打印“link”?
这是一个字典,您可以通过
等方式访问值r = search.result()
for d in r['search_result']:
print(d['link'])
没关系,我找到了答案。
import json
from youtubesearchpython import SearchVideos
search = SearchVideos("Video", offset = 1, mode = "json", max_results = 1)
r = search.result()
res = json.loads(r)
res1 = res['search_result']
res2 = res1[0]
res_fin = res2['link']
print(res_fin)
如果您想要更高级的功能,可以使用searchtube。它还为您提供过滤器选项。
pip install searchtube