无法在 void function.the 中打印出最多 6 的十进制数 function.the 值已正确检查 debugging.the 问题出在输出上

Question

**The void function automatically rounds off the value of a,b,c and prints out 0 instead of 0.5,0.33,0.166. I have checked the value of num1,num2,num3 and g they are correct just the problem is with the rounding off of the decimals of a,b and c.The setprecision function is also not working.

简单的概念是，当用户以数组形式输入时，我们必须计算正数的数量、负数的数量、零的数量（分别存储在 num1、num2、num3 中）。 **

  void plusMinus(vector<int> arr) {
   int g = arr.size();
   int num1=0; // Initialized value of num1.
   int num2=0; // Initialized value of num2.
   int num3=0;  // Initialized value of num3.

   for(int t=0;t<g;t++){
      if(arr[t]>0){
       num1++; 
      }
      else{
       if(arr[t]<0){
           num2++;
       }
      if(arr[t]==0){
          num3++; 
      }
      }
   }
           const  double a = num1/g; // made const due to the automatic rounding-off //
           const  double b = num2/g;  // made const due to the automatic rounding-off //
           const  double c = num3/g;   // made const due to the automatic rounding-off //
 
     cout << setprecision(6) << a << b << c; // The problem is with this line
}

Answer 1

你想让代码输出数字吗？ bc 在这种情况下，您需要系统输出变量 num1、num2 和 num3。

无法在 void function.the 中打印出最多 6 的十进制数 function.the 值已正确检查 debugging.the 问题出在输出上

Cannot print out decimal numbers upto 6 in a void function.the value are correct checked by debugging.the problem is with the output

c++

double

for-loop

decimal