如何在 java 中将布尔值与构造函数一起使用?
How to use boolean with constructor in java?
我们有一个 activity 可以存储和显示员工的信息。
我已经创建了名为 Person 的无修饰符 class 和名为 Employee 的 public class,这是主要方法。我的问题是我不知道如何在 class Person 中生成布尔值,它将在扫描仪的主要方法中使用。
class Person {
private String name;
private int contactNum;
private boolean status;
public boolean isRegular;
public String getName(){
return name;
}
public int getContactNum(){
return contactNum;
}
public void setName(String name){
this.name=name;
}
public void setContactNum(int contactNum){
this.contactNum=contactNum;
//how to make the boolean of status and isRegular?
}
}
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
Person P = new Person();
System.out.println("Type employee's name, contact number");
System.out.println("Press Enter after every input");
P.setName(input.nextLine());
P.setContactNum(input.nextInt());
System.out.println("Press Y if employee is regular or N if not");
//how to use boolean here that comes from the class Person?
System.out.println("Name: "+ P.getName());
System.out.println("Contact Number: "+ P.getContactNum());
System.out.println("Status:" + this is where the user is ask to Press Y if employee is regular or N if not )//the status is if the employee is regular or not.
我对您的代码的建议:
System.out.println("Press Y if employee is regular or any other key if not");
P.setRegular(input.nextLine().equalsIgnoreCase("Y"));
你的构造函数
public class Person {
private String name;
private int contactNum;
private boolean status;
private boolean isRegular;
//No arg constructor
public Person() {
}
//Full arg constructor
public Person(String name, int contactNum, boolean status, boolean isRegular) {
this.name = name;
this.contactNum = contactNum;
this.status = status;
this.isRegular = isRegular;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getContactNum() {
return contactNum;
}
public void setContactNum(int contactNum) {
this.contactNum = contactNum;
}
public boolean isStatus() {
return status;
}
public void setStatus(boolean status) {
this.status = status;
}
public boolean isRegular() {
return isRegular;
}
public void setRegular(boolean regular) {
isRegular = regular;
}
}
编辑
我注意到上面代码中的一个错误并修复了它。这一行应该是:
P.setRegular(input.next().equalsIgnoreCase("Y"));
您可以像打印任何其他 Java 原语一样打印布尔值。 `
System.out.println("Status:" + P.isRegular());
将打印 Status: true
或 Status: false
.
如果你想让它打印 Status: Yes
或 Status: No
,你可以这样做:
System.out.println("Status: ".concat((P.isRegular())?("Yes"):("No")));
我们有一个 activity 可以存储和显示员工的信息。 我已经创建了名为 Person 的无修饰符 class 和名为 Employee 的 public class,这是主要方法。我的问题是我不知道如何在 class Person 中生成布尔值,它将在扫描仪的主要方法中使用。
class Person {
private String name;
private int contactNum;
private boolean status;
public boolean isRegular;
public String getName(){
return name;
}
public int getContactNum(){
return contactNum;
}
public void setName(String name){
this.name=name;
}
public void setContactNum(int contactNum){
this.contactNum=contactNum;
//how to make the boolean of status and isRegular?
}
}
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
Person P = new Person();
System.out.println("Type employee's name, contact number");
System.out.println("Press Enter after every input");
P.setName(input.nextLine());
P.setContactNum(input.nextInt());
System.out.println("Press Y if employee is regular or N if not");
//how to use boolean here that comes from the class Person?
System.out.println("Name: "+ P.getName());
System.out.println("Contact Number: "+ P.getContactNum());
System.out.println("Status:" + this is where the user is ask to Press Y if employee is regular or N if not )//the status is if the employee is regular or not.
我对您的代码的建议:
System.out.println("Press Y if employee is regular or any other key if not");
P.setRegular(input.nextLine().equalsIgnoreCase("Y"));
你的构造函数
public class Person {
private String name;
private int contactNum;
private boolean status;
private boolean isRegular;
//No arg constructor
public Person() {
}
//Full arg constructor
public Person(String name, int contactNum, boolean status, boolean isRegular) {
this.name = name;
this.contactNum = contactNum;
this.status = status;
this.isRegular = isRegular;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getContactNum() {
return contactNum;
}
public void setContactNum(int contactNum) {
this.contactNum = contactNum;
}
public boolean isStatus() {
return status;
}
public void setStatus(boolean status) {
this.status = status;
}
public boolean isRegular() {
return isRegular;
}
public void setRegular(boolean regular) {
isRegular = regular;
}
}
编辑 我注意到上面代码中的一个错误并修复了它。这一行应该是:
P.setRegular(input.next().equalsIgnoreCase("Y"));
您可以像打印任何其他 Java 原语一样打印布尔值。 `
System.out.println("Status:" + P.isRegular());
将打印 Status: true
或 Status: false
.
如果你想让它打印 Status: Yes
或 Status: No
,你可以这样做:
System.out.println("Status: ".concat((P.isRegular())?("Yes"):("No")));