有没有办法在 python 中打印出 JSON 文件的某些元素?

Is there a way to print out certain elements of the JSON file in python?

我正在使用(荷兰语)天气 API,结果显示了很多信息。但是,我只想打印温度和位置。有没有办法过滤掉这些键?

from pip._vendor import requests
    

import json

response = requests.get(" http://weerlive.nl/api/json-data-10min.php?key=demo&locatie=52.0910879,5.1124231")


def jprint(obj):
    weer = json.dumps(obj, indent=2)
    print(weer)

jprint(response.json())

结果:

{
  "liveweer": [
    {
      "place": "Utrecht",
      "temp": "7.7",
      "gtemp": "5.2",
      "summa": "Dry after rain",
      "lv": "89",
       etc.

如何只打印地点和温度? 提前致谢

试试这个:

x=response.json()

print(x['liveweer'][0]['place'])
print(x['liveweer'][0]['temp'])

如果你希望API到returns你的列表位置,你可以这样做:

>>> {'liveweer': [{'plaats': item['plaats'], 'temp': item['temp']}] for item in response.json()['liveweer']}
{'liveweer': [{'plaats': 'Utrecht', 'temp': '8.0'}]}
import requests
response = requests.get(" http://weerlive.nl/api/json-data-10min.php?key=demo&locatie=52.0910879,5.1124231")
data = response.json()
for station in data["liveweer"]:
    print(f"Temp in {station['plaats']} is {station['temp']}")

输出

Temp in Utrecht is 8.0

请注意,您可以使用方便的 Response.json() 方法

如果您只对使用 place 和 temp 感兴趣,我建议您制作一本新词典。

import requests

r = requests.get(" http://weerlive.nl/api/json-data-10min.php?key=demo&locatie=52.0910879,5.1124231")

if r.status_code == 200:
    data = {
        "place" : r.json()['liveweer'][0]["place"], 
        "temp":  r.json()['liveweer'][0]["temp"],
    }
    print(data)