如何获得具有特定 属性 的嵌套对象的计数?
How can get a count with nested objects with a certain property?
好的,所以我正在使用 angular 将 json 保存到我的计算机以重新创建 github 成绩簿。
我可以通过 $http 请求获取数据,但看在我的份上,我只想计算标签 "Not Yet".
的问题数量
这里是 javascript:
$http.get('/api/github/repos/issues/all_issues/00All.json')
.then(function(response) {
console.log(response.data[0]);
var counter = 0;
for(var index = 0; index < response.data.length; index++) {
if(response.data[index].labels[0].name == "Not Yet") {
counter++;
};
};
console.log(counter);
});
这是最新的尝试,我也尝试过使用lodash来获得它:
$http.get('/api/github/repos/issues/all_issues/00All.json')
.then(function(response) {
console.log(response);
mile.notYet.width = _.forEach(response.data, function(n){
var counter = 0;
if(_.result(_.find(n.labels[0], 'name')) == "Not Yet") {
counter++;
}
console.log(counter);
counter = ((counter/10) * 100) + '%';
});
});
这是 json 数据的一部分:
[
{
"url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11",
"labels_url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11/labels{/name}",
"comments_url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11/comments",
"events_url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11/events",
"html_url": "https://github.com/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11",
"id": 73013825,
"number": 11,
"title": "00 -- Brace Yourself -- BEN GRIFFITH",
"user": {
"login": "Epicurean306",
"id": 11682684,
"avatar_url": "https://avatars.githubusercontent.com/u/11682684?v=3",
"gravatar_id": "",
"url": "https://api.github.com/users/Epicurean306",
"html_url": "https://github.com/Epicurean306",
"followers_url": "https://api.github.com/users/Epicurean306/followers",
"following_url": "https://api.github.com/users/Epicurean306/following{/other_user}",
"gists_url": "https://api.github.com/users/Epicurean306/gists{/gist_id}",
"starred_url": "https://api.github.com/users/Epicurean306/starred{/owner}{/repo}",
"subscriptions_url": "https://api.github.com/users/Epicurean306/subscriptions",
"organizations_url": "https://api.github.com/users/Epicurean306/orgs",
"repos_url": "https://api.github.com/users/Epicurean306/repos",
"events_url": "https://api.github.com/users/Epicurean306/events{/privacy}",
"received_events_url": "https://api.github.com/users/Epicurean306/received_events",
"type": "User",
"site_admin": false
},
"labels": [
{
"url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/labels/Not%20Yet",
"name": "Not Yet",
"color": "e11d21"
}
],
正如你所看到的标签属性是一个对象,嵌套在一个数组中,嵌套在一个对象中,嵌套在一个数组中,真可爱。放置标签 [0] 每次都会给我带来错误,并且不会让我计数。谁能告诉我我哪里搞砸了?谢谢!
您不需要 lodash 来完成任务
var cnt = response.data
.map(function(i) { return i.labels; })
// here we extract labels object only (and get an array of arrays of objects)
.map(function(i) { return i.filter(function(l) { return l.name == 'Not yet'; }).length; })
// then for every nested array we return a number of items with
// Not Yet names (and get an array of numbers)
.filter(function(c) { return c > 0; })
// then we filter issues that don't have one (and still get an array of numbers)
.length;
// and finally get length (which is a number)
如果您需要一个包含 lodash 的解决方案,它比原生高阶函数性能更高,那么您可以尝试下面的解决方案:
var size = _(response.data)
.pluck('labels')
.flatten()
.where({ name: 'Not Yet' })
.size();
更新:
如果您希望它具有更高的可重用性,您可以为克隆的链式序列保存一个引用,并简单地为该克隆序列提供另一个数组。
var data1 = [/*array from data1*/];
var data2 = [/*array from data2*/];
var notYetSequence = _(data1)
.pluck('labels')
.flatten()
.where({ name: 'Not Yet' });
notYetSequence.size(); // returns data 1 count
notYetSequence.plant(data2).size(); // returns data 2 count
作为比较,普通的 for 循环如下所示:
var data = response.data;
var count = 0;
var re = /not yet/i;
for (var a, i=0, iLen=data.length; i<iLen; i++) {
a = data[i].labels;
for (var j=0, jLen=a.length; j<jLen; j++) {
if (re.test(a[j].name)) ++count;
}
}
因此,无论哪种方式,实际上都没有太多代码,for 循环将与所有浏览器兼容(尽管使用 xmlHTTPRequest 意味着至少 ed 3+)并且速度最快……当然未经测试。 ;-)
好的,所以我正在使用 angular 将 json 保存到我的计算机以重新创建 github 成绩簿。
我可以通过 $http 请求获取数据,但看在我的份上,我只想计算标签 "Not Yet".
的问题数量这里是 javascript:
$http.get('/api/github/repos/issues/all_issues/00All.json')
.then(function(response) {
console.log(response.data[0]);
var counter = 0;
for(var index = 0; index < response.data.length; index++) {
if(response.data[index].labels[0].name == "Not Yet") {
counter++;
};
};
console.log(counter);
});
这是最新的尝试,我也尝试过使用lodash来获得它:
$http.get('/api/github/repos/issues/all_issues/00All.json')
.then(function(response) {
console.log(response);
mile.notYet.width = _.forEach(response.data, function(n){
var counter = 0;
if(_.result(_.find(n.labels[0], 'name')) == "Not Yet") {
counter++;
}
console.log(counter);
counter = ((counter/10) * 100) + '%';
});
});
这是 json 数据的一部分:
[
{
"url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11",
"labels_url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11/labels{/name}",
"comments_url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11/comments",
"events_url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11/events",
"html_url": "https://github.com/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11",
"id": 73013825,
"number": 11,
"title": "00 -- Brace Yourself -- BEN GRIFFITH",
"user": {
"login": "Epicurean306",
"id": 11682684,
"avatar_url": "https://avatars.githubusercontent.com/u/11682684?v=3",
"gravatar_id": "",
"url": "https://api.github.com/users/Epicurean306",
"html_url": "https://github.com/Epicurean306",
"followers_url": "https://api.github.com/users/Epicurean306/followers",
"following_url": "https://api.github.com/users/Epicurean306/following{/other_user}",
"gists_url": "https://api.github.com/users/Epicurean306/gists{/gist_id}",
"starred_url": "https://api.github.com/users/Epicurean306/starred{/owner}{/repo}",
"subscriptions_url": "https://api.github.com/users/Epicurean306/subscriptions",
"organizations_url": "https://api.github.com/users/Epicurean306/orgs",
"repos_url": "https://api.github.com/users/Epicurean306/repos",
"events_url": "https://api.github.com/users/Epicurean306/events{/privacy}",
"received_events_url": "https://api.github.com/users/Epicurean306/received_events",
"type": "User",
"site_admin": false
},
"labels": [
{
"url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/labels/Not%20Yet",
"name": "Not Yet",
"color": "e11d21"
}
],
正如你所看到的标签属性是一个对象,嵌套在一个数组中,嵌套在一个对象中,嵌套在一个数组中,真可爱。放置标签 [0] 每次都会给我带来错误,并且不会让我计数。谁能告诉我我哪里搞砸了?谢谢!
您不需要 lodash 来完成任务
var cnt = response.data
.map(function(i) { return i.labels; })
// here we extract labels object only (and get an array of arrays of objects)
.map(function(i) { return i.filter(function(l) { return l.name == 'Not yet'; }).length; })
// then for every nested array we return a number of items with
// Not Yet names (and get an array of numbers)
.filter(function(c) { return c > 0; })
// then we filter issues that don't have one (and still get an array of numbers)
.length;
// and finally get length (which is a number)
如果您需要一个包含 lodash 的解决方案,它比原生高阶函数性能更高,那么您可以尝试下面的解决方案:
var size = _(response.data)
.pluck('labels')
.flatten()
.where({ name: 'Not Yet' })
.size();
更新:
如果您希望它具有更高的可重用性,您可以为克隆的链式序列保存一个引用,并简单地为该克隆序列提供另一个数组。
var data1 = [/*array from data1*/];
var data2 = [/*array from data2*/];
var notYetSequence = _(data1)
.pluck('labels')
.flatten()
.where({ name: 'Not Yet' });
notYetSequence.size(); // returns data 1 count
notYetSequence.plant(data2).size(); // returns data 2 count
作为比较,普通的 for 循环如下所示:
var data = response.data;
var count = 0;
var re = /not yet/i;
for (var a, i=0, iLen=data.length; i<iLen; i++) {
a = data[i].labels;
for (var j=0, jLen=a.length; j<jLen; j++) {
if (re.test(a[j].name)) ++count;
}
}
因此,无论哪种方式,实际上都没有太多代码,for 循环将与所有浏览器兼容(尽管使用 xmlHTTPRequest 意味着至少 ed 3+)并且速度最快……当然未经测试。 ;-)