Python 忽略具有多个模式匹配的行

Question

我有如下列表：

Index1_list=['ATTACTCG','TCCGGAGA','CGCTCATT','GAGATTCC','ATTCAGAA']

我想做的是在行中只有一个列表元素时保存行 (not two different or three different)

>seq1
NNNNNNNNNNNNNNNNATTACTCGNNNNNNNNNNNGAGATTCCNNNNN
>seq2
NNNNNNNNNNNNNATTACTCGNNNNNNNNNN
>seq3
NNNNNNNNNNNNNGAGATTCCNNNNNNNNNNN

输出应该是

>seq2
NNNNNNNNNNNNNATTACTCGNNNNNNNNNN
>seq3
NNNNNNNNNNNNNGAGATTCCNNNNNNNNNNN

我使用了下面的脚本，但未能过滤掉具有两个不同匹配项的读数。

from Bio import SeqIO

Index1_list=['ATTACTCG','TCCGGAGA','CGCTCATT','GAGATTCC','ATTCAGAA']


with open('All.fastq','r') as R1:
    for record in SeqIO.parse(R1,'fasta'):
        for i in Index1_list:
            if i in record.seq:
                sequences = record.format('fasta')
                print(sequences)

谢谢。

Answer 1

您应该能够通过检查列表中有多少元素在所需的字符串中来执行您想要的操作，如下所示：

from Bio import SeqIO

Index1_list=['ATTACTCG','TCCGGAGA','CGCTCATT','GAGATTCC','ATTCAGAA']


with open('All.fastq','r') as R1:
    for record in SeqIO.parse(R1,'fasta'):
        count = 0

        for i in Index1_list:
            if i in record.seq:
                count += 1

        if count == 1:
            sequences = record.format('fasta')
            print(sequences)

Python 忽略具有多个模式匹配的行

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