连接两个具有重叠日期索引的数据帧，结果数据帧默认为 "left"，除了 "left" 是 NaN

Question

下面给出DF1和DF2，如何得到DFresult？

DF1:                        DF2:                        DFresult:       
Date | Value                Date | Value                Date | Value
------------                ------------                ------------
1-01-2019 | 1                                           1-01-2019 | 1       (no overlap, take the one that exists)
1-02-2019 | 1                                           1-02-2019 | 1       (no overlap, take the one that exists)
1-03-2019 | np.NaN          1-03-2019 | 2               1-03-2019 | 2       (left is NaN, take right)
1-04-2019 | 1               1-04-2019 | np.NaN          1-04-2019 | 1       (left is not NaN, take left)
1-05-2019 | np.NaN          1-05-2019 | np.NaN          1-05-2019 | np.NaN  (both NaN, keep it)
1-06-2019 | 1               1-06-2019 | 2               1-06-2019 | 1       (left is not NaN, take left)
                            1-07-2019 | 2               1-07-2019 | 2       (no overlap, take the one that exists)
                            1-08-2019 | 2               1-08-2019 | 2       (no overlap, take the one that exists)
                            1-09-2019 | 2               1-09-2019 | 2       (no overlap, take the one that exists)
                            1-10-2019 | 2               1-10-2019 | 2       (no overlap, take the one that exists)
                            1-11-2019 | 2               1-11-2019 | 2       (no overlap, take the one that exists)

如果我想使用函数来确定重叠决策怎么办？例如，如果 left 高于 right，或者 left 为 NaN，则取 left：

DF1:                        DF2:                        DFresult:       
Date | Value                Date | Value                Date | Value
------------                ------------                ------------
1-01-2019 | 1                                           1-01-2019 | 1       (no overlap, take the one that exists)
1-02-2019 | 1                                           1-02-2019 | 1       (no overlap, take the one that exists)
1-03-2019 | np.NaN          1-03-2019 | 2               1-03-2019 | 2       (left is NaN, take right)
1-04-2019 | 1               1-04-2019 | np.NaN          1-04-2019 | 1       (right is NaN, take left)
1-05-2019 | np.NaN          1-05-2019 | np.NaN          1-05-2019 | np.NaN  (both NaN, keep it)
1-06-2019 | 1               1-06-2019 | 2               1-06-2019 | 2       (left is not higher, take right)
1-06-2019 | 3               1-07-2019 | 2               1-07-2019 | 3       (left is higher, take left)
1-06-2019 | 1               1-08-2019 | 2               1-08-2019 | 2       (left is not higher, take right)
                            1-09-2019 | 2               1-09-2019 | 2       (no overlap, take the one that exists)
                            1-10-2019 | 2               1-10-2019 | 2       (no overlap, take the one that exists)
                            1-11-2019 | 2               1-11-2019 | 2       (no overlap, take the one that exists)

Answer 1

试试

out = pd.concat([DF1,DF2]).groupby('Date',as_index=False).max()
# for your original one 

#out = pd.concat([DF1,DF2]).groupby('Date',as_index=False).first()

连接两个具有重叠日期索引的数据帧，结果数据帧默认为 "left"，除了 "left" 是 NaN

Concatenate two dataframes, with some overlaping date index, with resulting dataframe taking "left" as default, except the "left" is NaN

python

concatenation

overlap

dataframe

pandas