如何在 C# 中将 int Random 乘以 int

Question

我遇到了一个小问题 - 我正在尝试在控制台应用程序中将 random 乘以 int。我有一个错误：

Operator '*' cannot be applied to operands of Type 'Random' and 'int'

我骑过：rndAttackPoints = attackPoints然后

这个int damagePoints = (rndAttackPoints * strenghtPoints1) - defencePoints1;变成

这个 int damagePoints = (attackPoints * strenghtPoints1) - defencePoints1; 但这没有用。

所以我问你，你知道如何在 C# 中将 Random 乘以 int 吗？

            //Elf
            int healthPoints1 = 100;
            int defencePoints1 = 3;
            int strenghtPoints1 = 2;

            // Goblin
            int healthPoints2 = 100;
            int defencePoints2 = 5;
            int strenghtPoints2 = 1;

            Random rndAttackPoints = new Random();            
            Console.WriteLine($"You've attacked: {rndAttackPoints.Next(5, 10)} HP");

            int damagePoints = (rndAttackPoints * strenghtPoints1) - defencePoints1;

Answer 1

将随机值保存在一个单独的变量中并按如下方式使用它：

Random rndAttackPoints = new Random();
int rnd = rndAttackPoints.Next(5, 10);
Console.WriteLine($"You've attacked: {rnd} HP");

int damagePoints = (rnd * strenghtPoints1) - defencePoints1;