Oracle:每个组的 SUM 的 MAX

Oracle: MAX of SUM of Each Group

我的场景是使用子查询显示每个酒店分店维护成本最高的酒店房间。我有三个单独的表:branchroommaintenance.

Table branch

id             NUMBER(3) PRIMARY KEY
location       VARCHAR2(20)

Table room

id             NUMBER(3) PRIMARY KEY
room_number    CHAR(4)
branch_id      NUMBER(3)

Table maintenance

id             NUMBER(3) PRIMARY KEY
room_id        NUMBER(3)
cost           NUMBER(4)

我想要的输出格式为

location | room_number | cost
-------------------------------
         |             |
         |             |
         |             |

我不确定如何 select 添加每个房间的总成本后每个分支的最大值。请指教

您可以使用 window 函数:

select *
from (
    select b.location, r.room_number, m.cost, 
        rank() over(partition by b.id order by m.cost desc) rn
    from branch b
    inner join room r on r.branch_id = b.id
    inner join maintenance m on m.room_id = r.id
) t
where rn = 1

如果一个房间可能有多次维护,那么我们需要聚合:

select *
from (
    select b.location, r.room_number, sum(m.cost) as cost, 
        rank() over(partition by b.id order by sum(m.cost) desc) rn
    from branch b
    inner join room r on r.branch_id = b.id
    inner join maintenance m on m.room_id = r.id
    group by b.id, b.location, r.room_number
) t
where rn = 1

您可以使用 ROW_NUMBER() 分析函数以及连接这些表

SELECT location, room_number, cost
  FROM (SELECT b.location,
               r.room_number,
               m.cost,
               ROW_NUMBER() OVER(PARTITION BY r.branch_id ORDER BY m.cost DESC) AS rn
          FROM branch b
          JOIN room r
            ON r.branch_id = b.id
          JOIN maintenance m
            ON m.room_id = r.id)
 WHERE rn = 1

P.S。如果关系(成本的相等值)很重要(即使生成额外行的最大成本值没有问题也应该包括在内),那么您可以将 ROW_NUMBER() 替换为 DENSE_RANK()