在cpp中将十六进制字符串转换为字符数组

Question

我在 cpp 中有一个十六进制字符串

std::string str = "fe800000000000000cd86d653903694b";

我想把它转换成这样存储的字符数组

unsigned char ch[16] =     { 0xfe, 0x80, 0x00, 0x00,
                             0x00, 0x00, 0x00, 0x00,
                             0x0c, 0xd8, 0x6d, 0x65,
                             0x39, 0x03, 0x69, 0x4b };

我正在考虑一次遍历字符串2个字符并将其存储在字符数组中。但是我找不到任何对这里有帮助的库函数。

for (size_t i = 0; i < str.length(); i += 2) 
{ 
      string part = hex.substr(i, 2); 
      //convert part to hex format and store it in ch
}

感谢任何帮助

Answer 1

我不是 C++ 专家，肯定有更好的东西，但是因为没有人回答...

#include <iostream>

int main()
{
    std::string str = "fe800000000000000cd86d653903694b";
    unsigned char ch[16];

    for (size_t i = 0; i < str.length(); i += 2) 
    { 
        // Assign each pair converted to an integer
        ch[i / 2] = std::stoi(str.substr(i, 2), nullptr, 16);
    }
    for (size_t i = 0; i < sizeof ch; i++) 
    { 
        // Print each character as hex
        std::cout << std::hex << +ch[i];
    }
    std::cout << '\n';
}

如果您事先不知道 str 的长度：

#include <iostream>
#include <vector>

int main()
{
    std::string str = "fe800000000000000cd86d653903694b";
    std::vector<unsigned char> ch;

    for (size_t i = 0; i < str.length(); i += 2) 
    { 
        ch.push_back(std::stoi(str.substr(i, 2), nullptr, 16));
    }
    for (size_t i = 0; i < ch.size(); i++) 
    { 
        std::cout << std::hex << +ch[i];
    }
    std::cout << '\n';
}

在cpp中将十六进制字符串转换为字符数组

Convert hex string to character array in cpp

c++

arrays

string

hex

char