使用 lambda 在 Python Tkinter Tic Tac Toe 中不可调用列表

Question

在我的代码中，我需要使用 Lambda 来创建按钮板，但是我在尝试调用按钮时遇到错误。我已经尝试按照我在另一个论坛中看到的建议将 () 切换为 []，但是我无法使其工作。

from tkinter import *
import tkinter.font as font

root = Tk()
root.geometry("500x500")

myFont = font.Font(family = "Courier", size = 80)

who = True
turn = 0

#changing turns and choosing tiles
def update(x,y):
    global who, turn
    if board(x,y)["text"] == "-" and who == True:#<-----------Error
        board(x,y)["text"] = "X"
        who = False
        turn += 1
    elif board(x,y)["text"] == "-" and who == False:
        board(x,y)["text"] = "0"
        who = True
        turn += 1
    else:
        print("That Box has already been chosen")
    
    
    
board = [[Button(root, text = "-", font = myFont, command = (lambda x = x, y = y: update(x,y))) for y in range(3)] for x in range(3)]
#^^^^^ The cause of my frustration

for x in range(3):
    for y in range(3):
        board[x][y].grid(row=x,column=y)


root.mainloop()

Answer 1

应该是

if board[x][y]["text"] == "-"

就像在网格循环中一样。

使用 lambda 在 Python Tkinter Tic Tac Toe 中不可调用列表

List not callable in Python Tkinter Tic Tac Toe using lambda

python

tkinter

tic-tac-toe