带 Python 的星图

Question

我遇到了 this article。不知是否可以用Python做成星图？（见图）。
我看过 matplotlib 和 seaborn 画廊，但显然它们没有任何内置函数来创建这样的图表（也不是雷达图）。

有什么方法可以使用Python轻松绘制这样的图表吗？

Answer 1

以下是根据您的规格对 StellarChart 的演绎。
它派生自 SpiderChart (RadarChart) 构建 tkinter 来回答 earlier question

您可以在下面并排看到它们：

它需要一个元组列表('label', score)，分数以百分比表示（区间[0, 100]中的值）。

数据点的数量根据提供的数据进行调整。
图表的比例可以调整。

import math
import tkinter as tk


class SpiderChart(tk.Canvas):
    """a canvas that displays datapoints as a SpiderChart
    """
    width=500
    height=500
    def __init__(self, master, datapoints, concentrics=10, scale=200):
        super().__init__(master, width=self.width, height=self.height)
        self.scale = scale
        self.center = self.width // 2, self.height // 2
        self.labels = tuple(d[0] for d in datapoints)
        self.values = tuple(d[1] for d in datapoints)
        self.num_pts = len(self.labels)
        self.concentrics = [n/(concentrics) for n in range(1, concentrics + 1)]
        self.draw()
        
    def position(self, x, y):
        """use +Y pointing up, and origin at center
        """
        cx, cy = self.center
        return x + cx, cy - y
    
    def draw_circle_from_radius_center(self, radius):
        rad = radius * self.scale
        x0, y0 =  self.position(-rad, rad)
        x1, y1 =  self.position(rad, -rad)
        return self.create_oval(x0, y0, x1, y1, dash=(1, 3))
    
    def draw_label(self, idx, label):
        angle = idx * (2 * math.pi) / self.num_pts
        d = self.concentrics[-1] * self.scale
        x, y = d * math.cos(angle), d * math.sin(angle)
        self.create_line(*self.center, *self.position(x, y), dash=(1, 3))
        d *= 1.1 
        x, y = d * math.cos(angle), d * math.sin(angle)
        self.create_text(*self.position(x, y), text=label)
        
    def draw_polygon(self):
        points = []
        for idx, val in enumerate(self.values):
            d = (val / 100) * self.scale
            angle = idx * (2 * math.pi) / self.num_pts
            x, y = d * math.cos(angle), d * math.sin(angle)
            points.append(self.position(x, y))
        self.create_polygon(points, fill='cyan')
        
    def draw(self):
        self.draw_polygon()
        for concentric in self.concentrics:
            self.draw_circle_from_radius_center(concentric)
        for idx, label in enumerate(self.labels):
            self.draw_label(idx, label)
            
            
class StellarChart(SpiderChart):
    """a canvas that displays datapoints as a StellarChart
    """        
    def draw_polygon(self):
        points = []
        da = math.pi / self.num_pts
        b = .05 * self.scale
        for idx, val in enumerate(self.values):
            d = (val / 100) * self.scale
            angle = idx * (2 * math.pi) / self.num_pts
            x, y = d * math.cos(angle), d * math.sin(angle)
            points.append(self.position(x, y))
            xb, yb = b * math.cos(angle + da), b * math.sin(angle+da)
            points.append(self.position(xb, yb))
        self.create_polygon(points, width=3, outline='red', fill='pink', join=tk.ROUND)

            
data = [('stamina', 70), ('python-skill', 100), ('strength', 80), ('break-dance', 66), ('speed', 45), ('health', 72), ('healing', 90), ('energy', 12), ('libido', 100)]

root = tk.Tk()

stellar = StellarChart(root, data)
stellar.pack(side=tk.LEFT)

spider = SpiderChart(root, data)
spider.pack(side=tk.LEFT)

root.mainloop()

Answer 2

Plotly 库包含一个星图：https://plotly.com/python/radar-chart/

带 Python 的星图

Stellar chart with Python

python

tkinter

matplotlib

python-3.x

tkinter-canvas