如何在按下 tkinter 时更改按钮状态

Question

我正在编写一个可以做很多事情的计算器，我想问一下如何在按下按钮时更改按钮状态。我正在使用以下代码：

import math, sqlite3
from tkinter import *


root = Tk()
x_are = Label(root)
x_are.grid(row=0, column=0)
x_are_ = Label(root)
x_are_.grid(row=0, column=0)
boo = True
bool_ = True


formula_entry = ''
def geometric_calc_press():
    global bool_
    def formula():
        global bool_, state, formula_entry
        if bool_:
            formula_entry = Entry(geometric_calc, width=66)
            formula_entry.grid(row=1, column=0, columnspan=1000)
            bool_ = False
        def show_searched_formula():
            global formula_entry
            x = formula_entry.get()
            print(x)
        def close():
            global bool_, state, formula_entry, close, search_
            bool_ = True
            formula_entry.destroy()
            close_.destroy()
            search.destroy()
        if not bool_:
            close_ = Button(geometric_calc, text='Close', command=close, bg='black', fg='lime', highlightcolor="lime", highlightbackground="lime",
                           highlightthickness=2, relief=SOLID, default='active', padx=80, pady=20)
            close_.grid(row=3, column=0)

            search = Button(geometric_calc, text='Search', command=show_searched_formula, bg='black', fg='lime', highlightcolor="lime", highlightbackground="lime",
                           highlightthickness=2, relief=SOLID, default='active', padx=77, pady=20)
            search.grid(row=2, column=0)




    global root
    root.destroy()
    geometric_calc = Tk()
    bindings = {
        '<FocusIn>': {'default': 'active'},
        '<FocusOut>': {'default': 'active'}
    }
    for k, v in bindings.items():
        geometric_calc.bind_class('Button', k, lambda e, kwarg=v: e.widget.config(**kwarg))

    geometric_calc.geometry('400x415')
    geometric_calc.config(bg='black')
    formula_finder = Button(geometric_calc, text='Formulas', bg='black', fg='lime', highlightcolor="lime",
                            highlightbackground="lime", highlightthickness=2, relief=SOLID, default='active', padx=70,
                            command=formula)
    formula_finder.grid(row=0, column=0)

    formula_user = Button(geometric_calc, text='Calculate', bg='black', fg='lime', highlightcolor="lime",
                            highlightbackground="lime", highlightthickness=2, relief=SOLID, default='active', padx=70)
    formula_user.grid(row=0, column=2)

唯一真正相关的部分是 geometric_calc_press 函数。我希望能够修复一个错误，如果多次按下公式按钮，关闭按钮将无法正常工作（关闭按钮需要按下相同的次数。）所以我想在按下时禁用公式按钮直到关闭按钮被按下。我真的不知道该怎么做，所以我在这里问。

Answer 1

您可以使用

停用按钮

button.config(state="disabled")

然后用

激活它

button.config(state="normal")

或

button.config(state="active")

顺便说一句： 您也可以用同样的方式停用其他小部件 - 即。 Label、Entry 等。其他小部件可能具有不同的状态 - 即。 Entry 有状态 "read-only"（但它没有 "active"）

最小工作示例

import tkinter as tk  # PEP8: `import *` is not preferred

# --- functions ---

def on_press_1():
    b1.config(state="disabled")
    l1.config(state="disabled")
    e1.config(state="disabled")  # or `readonly`

def on_press_2():
    b1.config(state="normal")  # or `active`
    l1.config(state="normal")  # or `active`
    e1.config(state="normal")

# --- main ---

root = tk.Tk()

l1 = tk.Label(root, text="Label Text")
l1.pack()

e1 = tk.Entry(root)
e1.insert(0, "Entry Text")
e1.pack()

b1 = tk.Button(root, text="Deactivate", command=on_press_1)
b1.pack()

b2 = tk.Button(root, text="Activate", command=on_press_2)
b2.pack()

root.mainloop()

如何在按下 tkinter 时更改按钮状态

How to change button state upon press tkinter

python

tkinter

widget

button