使用 Python 解析包含唯一模式的文本文件

Question

如何解析包含此模式“KEYWORD: Out:”的文本文件并使用 Python 将结果转储到输出文件？

input.txt

DEBUG 2020-11:11:17.401 KEYWORD: Out:0xaaaf0000 In:0x80000000.1110ffff.
DEBUG 2020-11:11:17.401 KEYWORD: Out:0xaaaf00cc In:0x80000000.1110ffaa.

output.txt

0xaaaf0000:1110ffff 
0x80000000:1110ffaa

Answer 1

您可以使用正则表达式：

import re 

txt='''\
DEBUG 2020-11:11:17.401 KEYWORD: Out:0xaaaf0000 In:0x80000000.1110ffff.
DEBUG 2020-11:11:17.401 KEYWORD: Out:0xaaaf00cc In:0x80000000.1110ffaa.'''

pat=r'KEYWORD: Out:(0x[a-f0-9]+)[ \t]+In:0x[a-f0-9]+\.([a-f0-9]+)'

>>> '\n'.join([m[0]+':'+m[1] for m in re.findall(pat, txt)])
0xaaaf0000:1110ffff
0xaaaf00cc:1110ffaa

如果您想从文件中逐行执行此操作：

import re

pat=r'KEYWORD: Out:(0x[a-f0-9]+)[ \t]+In:0x[a-f0-9]+\.([a-f0-9]+)'

with open(ur_file) as f:
    for line in f:
        m=re.search(pat, line) 
        if m:
            print(m.group(1)+':'+m.group(2))

Answer 2

In [6]: lines
Out[6]:
['DEBUG 2020-11:11:17.401 KEYWORD: Out:0xaaaf0000 In:0x80000000.1110ffff.',
 'DEBUG 2020-11:11:17.401 KEYWORD: Out:0xaaaf00cc In:0x80000000.1110ffaa.']

In [7]: [x.split('Out:')[1].split(' ')[0] + ':' + x.split('In:')[1].split('.')[1] for x in lines]
Out[7]: ['0xaaaf0000:1110ffff', '0xaaaf00cc:1110ffaa']

Answer 3

我认为您的 'output.txt' 的第 2 行可能有误（如果没有，则很复杂 - 您需要指出这一点）。

否则，可能是这样的正则表达式：

(.*Out:)(0x[0-9a-f]{1,8}) In:0x[0-9a-f]{1,8}\.([0-9a-f]{1,8}).

https://regex101.com/r/lMrR06/2

使用 Python 解析包含唯一模式的文本文件

Parsing text file containing unique pattern using Python

python

python-2.7

python-3.x