如何将列表合并到 Elixir 中的元组列表中？

Question

Elixir 将两个列表合并为一个元组列表的方法是什么？

list1 = [1, 2, 3, 4]
list2 = [5, 6, 7, 8]

# List of tuples from 'list1' and 'list2':
    
result = [{1,5}, {2,6}, {3,7}, {4,8}]

result的每个成员都是一个元组，第一个成员来自list1，第二个成员来自list2。

Answer 1

您可以使用 Enum.zip/2:

Zips corresponding elements from a finite collection of enumerables into one list of tuples.

Enum.zip([[1, 2, 3], [:a, :b, :c], ["foo", "bar", "baz"]])
# [{1, :a, "foo"}, {2, :b, "bar"}, {3, :c, "baz"}]

Enum.zip([[1, 2, 3, 4, 5], [:a, :b, :c]])
# [{1, :a}, {2, :b}, {3, :c}]

Answer 2

您可以考虑使用 List.zip/1:

zip(list_of_lists)

Specs

zip([list()]) :: [tuple()]

Zips corresponding elements from each list in list_of_lists.

The zipping finishes as soon as any list terminates.

示例：

    iex(1)> list1 = [1, 2, 3, 4]
    [1, 2, 3, 4]
    iex(2)> list2 = [5, 6, 7, 8]
    [5, 6, 7, 8]
    iex(3)> result = List.zip([list1, list2])
    [{1, 5}, {2, 6}, {3, 7}, {4, 8}]

如何将列表合并到 Elixir 中的元组列表中？

How to merge lists into a list of tuples in Elixir?

tuples

list

elixir