Google 表格脚本 - 按多个动态范围排序
Google Sheets Script - Sort By Multiple, Dynamic Ranges
*TL:DR
我想根据以下条件自动对整个 sheet 进行排序。
- 按第 1、2 和 3 列对整个 sheet 进行排序
- 将第 1 列中带有“Z Shipped”的任何行移动到 populated 列表的底部(第 1 列中有很多行的空白数据,所以我想要“其他data, Z Shipped data, 空行".*
您好,正如标题所述,我正在尝试通过多个范围对 google sheet 进行排序。我已经在下面粘贴了我发现让我接近的当前代码,但是我不断收到
“范围的坐标超出了sheet的维度。”
第二行“newRange.sort(newSortOrder)”出错。
我不确定我当前的代码是否是我需要的。我没有这方面的专业知识,只是试图找到可以在线工作的功能,但由于这似乎不是一个常见的要求,所以我被困在了这个功能上。
function autosort() {
var ss = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
var sortRange = "A3:E";
var range = ss.getRange(sortRange);
var sortOrder = [
{column: 1, ascending: true},
{column: 2, ascending: true},
{column: 3, ascending: true}
];
range.sort(sortOrder);
var status = ss.getDataRange().getLastRow();
for (var i=status;i>=1;i--){
if(ss.getRange(i,1).getValue()!=='Z Shipped') {break;}
}
var newSortRow = i+1;
var newSortRange = "A3:E"+newSortRow;
var newRange = ss.getRange(newSortRange);
var newSortOrder = [
{column: 2, ascending: true},
{column: 3, ascending: true}
];
newRange.sort(newSortOrder);
}
“我想要”其他数据,Z Shipped 数据,空行
我们分两个阶段排序。
首先,按第 1、2 和 3 列对整个 sheet 进行排序。
然后找到“Z Shipped”块的边界并将其移动到填充列表的底部。
function autosort() {
let ss = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
let sortRange = "A3:E";
var range = ss.getRange(sortRange);
let sortOrder = [
{column: 1, ascending: true},
{column: 2, ascending: true},
{column: 3, ascending: true}
];
range.sort(sortOrder);
// Find the boundaries of the "Z Shipped" block
let Avals = ss.getRange("A3:A").getValues();
let fAvals = [].concat(...Avals); // Make the array flat
let start = fAvals.indexOf("Z Shipped");
let end = fAvals.lastIndexOf("Z Shipped");
// Load data with non-empty column A into an array
let Alast = Avals.filter(String).length + 2;
let vals = ss.getRange("A3:E" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed = vals.splice(start, end - start + 1);
let sorted = vals.concat(removed);
ss.getRange("A3:E" + Alast).setValues(sorted);
}
编辑:代码已更新,因此它可以解决我计算某些列的数组公式。基本上只需要确定每个数组列周围的范围。
非常感谢@Boris Baublys 在这方面的帮助!
我在提供样本数据时确实稍微调整了代码,但我的真实数据与提供的代码并不完全一致。可能有一种方法可以进一步清理我调整后的代码,但它对我有用!
基本上,新代码会对“非 Z 发货”数据进行最终排序,以从那里将其放入正确的顺序,并指定要排序的 sheet。
// Sort entire sheet by a specified sort order
function autosort() {
let ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheetByName("Sheet Name");
let sortRange = "A3:BH";
var range = sheet.getRange(sortRange);
let sortOrder = [
{column: 1, ascending: true},
{column: 11, ascending: true},
];
range.sort(sortOrder);
// Find the boundaries of a specified block of entries ("Z Shipped" here).
let Avals = sheet.getRange("A3:A").getValues();
let fAvals = [].concat(...Avals); // Make the array flat
let start = fAvals.indexOf("Z Shipped");
let end = fAvals.lastIndexOf("Z Shipped");
/////
// Load data with non-empty column A into an array
let Alast = Avals.filter(String).length + 2;
let vals1 = sheet.getRange("A3:O" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed1 = vals1.splice(start, end - start + 1);
let sorted1 = vals1.concat(removed1);
sheet.getRange("A3:O" + Alast).setValues(sorted1);
/////
// Load data with non-empty column A into an array
let vals2 = sheet.getRange("S3:AW" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed2 = vals2.splice(start, end - start + 1);
let sorted2 = vals2.concat(removed2);
sheet.getRange("S3:AW" + Alast).setValues(sorted2);
/////
// Load data with non-empty column A into an array
let vals3 = sheet.getRange("AY3:BD" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed3 = vals3.splice(start, end - start + 1);
let sorted3 = vals3.concat(removed3);
sheet.getRange("AY3:BD" + Alast).setValues(sorted3);
/////
// Load data with non-empty column A into an array
let vals4 = sheet.getRange("BF3:BF" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed4 = vals4.splice(start, end - start + 1);
let sorted4 = vals4.concat(removed4);
sheet.getRange("BF3:BF" + Alast).setValues(sorted4);
/////
// Load data with non-empty column A into an array
let vals5 = sheet.getRange("BH3:BH" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed5 = vals5.splice(start, end - start + 1);
let sorted5 = vals5.concat(removed5);
sheet.getRange("BH3:BH" + Alast).setValues(sorted5);
/////
// Sort all the non "Z Shipped" items with a new sort order
let sortRange2 = ("A3:BH" + start);
var range2 = sheet.getRange(sortRange2);
let sortOrder2 = [
{column: 6, ascending: true},
{column: 11, ascending: true},
{column: 4, ascending: true}
];
range2.sort(sortOrder2);
}
再次非常感谢@Boris Baublys
*TL:DR 我想根据以下条件自动对整个 sheet 进行排序。
- 按第 1、2 和 3 列对整个 sheet 进行排序
- 将第 1 列中带有“Z Shipped”的任何行移动到 populated 列表的底部(第 1 列中有很多行的空白数据,所以我想要“其他data, Z Shipped data, 空行".*
您好,正如标题所述,我正在尝试通过多个范围对 google sheet 进行排序。我已经在下面粘贴了我发现让我接近的当前代码,但是我不断收到
“范围的坐标超出了sheet的维度。”
第二行“newRange.sort(newSortOrder)”出错。
我不确定我当前的代码是否是我需要的。我没有这方面的专业知识,只是试图找到可以在线工作的功能,但由于这似乎不是一个常见的要求,所以我被困在了这个功能上。
function autosort() {
var ss = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
var sortRange = "A3:E";
var range = ss.getRange(sortRange);
var sortOrder = [
{column: 1, ascending: true},
{column: 2, ascending: true},
{column: 3, ascending: true}
];
range.sort(sortOrder);
var status = ss.getDataRange().getLastRow();
for (var i=status;i>=1;i--){
if(ss.getRange(i,1).getValue()!=='Z Shipped') {break;}
}
var newSortRow = i+1;
var newSortRange = "A3:E"+newSortRow;
var newRange = ss.getRange(newSortRange);
var newSortOrder = [
{column: 2, ascending: true},
{column: 3, ascending: true}
];
newRange.sort(newSortOrder);
}
“我想要”其他数据,Z Shipped 数据,空行
我们分两个阶段排序。 首先,按第 1、2 和 3 列对整个 sheet 进行排序。 然后找到“Z Shipped”块的边界并将其移动到填充列表的底部。
function autosort() {
let ss = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
let sortRange = "A3:E";
var range = ss.getRange(sortRange);
let sortOrder = [
{column: 1, ascending: true},
{column: 2, ascending: true},
{column: 3, ascending: true}
];
range.sort(sortOrder);
// Find the boundaries of the "Z Shipped" block
let Avals = ss.getRange("A3:A").getValues();
let fAvals = [].concat(...Avals); // Make the array flat
let start = fAvals.indexOf("Z Shipped");
let end = fAvals.lastIndexOf("Z Shipped");
// Load data with non-empty column A into an array
let Alast = Avals.filter(String).length + 2;
let vals = ss.getRange("A3:E" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed = vals.splice(start, end - start + 1);
let sorted = vals.concat(removed);
ss.getRange("A3:E" + Alast).setValues(sorted);
}
编辑:代码已更新,因此它可以解决我计算某些列的数组公式。基本上只需要确定每个数组列周围的范围。
非常感谢@Boris Baublys 在这方面的帮助!
我在提供样本数据时确实稍微调整了代码,但我的真实数据与提供的代码并不完全一致。可能有一种方法可以进一步清理我调整后的代码,但它对我有用!
基本上,新代码会对“非 Z 发货”数据进行最终排序,以从那里将其放入正确的顺序,并指定要排序的 sheet。
// Sort entire sheet by a specified sort order
function autosort() {
let ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheetByName("Sheet Name");
let sortRange = "A3:BH";
var range = sheet.getRange(sortRange);
let sortOrder = [
{column: 1, ascending: true},
{column: 11, ascending: true},
];
range.sort(sortOrder);
// Find the boundaries of a specified block of entries ("Z Shipped" here).
let Avals = sheet.getRange("A3:A").getValues();
let fAvals = [].concat(...Avals); // Make the array flat
let start = fAvals.indexOf("Z Shipped");
let end = fAvals.lastIndexOf("Z Shipped");
/////
// Load data with non-empty column A into an array
let Alast = Avals.filter(String).length + 2;
let vals1 = sheet.getRange("A3:O" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed1 = vals1.splice(start, end - start + 1);
let sorted1 = vals1.concat(removed1);
sheet.getRange("A3:O" + Alast).setValues(sorted1);
/////
// Load data with non-empty column A into an array
let vals2 = sheet.getRange("S3:AW" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed2 = vals2.splice(start, end - start + 1);
let sorted2 = vals2.concat(removed2);
sheet.getRange("S3:AW" + Alast).setValues(sorted2);
/////
// Load data with non-empty column A into an array
let vals3 = sheet.getRange("AY3:BD" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed3 = vals3.splice(start, end - start + 1);
let sorted3 = vals3.concat(removed3);
sheet.getRange("AY3:BD" + Alast).setValues(sorted3);
/////
// Load data with non-empty column A into an array
let vals4 = sheet.getRange("BF3:BF" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed4 = vals4.splice(start, end - start + 1);
let sorted4 = vals4.concat(removed4);
sheet.getRange("BF3:BF" + Alast).setValues(sorted4);
/////
// Load data with non-empty column A into an array
let vals5 = sheet.getRange("BH3:BH" + Alast).getValues();
// Move the "Z Shipped" block to the end of the array
let removed5 = vals5.splice(start, end - start + 1);
let sorted5 = vals5.concat(removed5);
sheet.getRange("BH3:BH" + Alast).setValues(sorted5);
/////
// Sort all the non "Z Shipped" items with a new sort order
let sortRange2 = ("A3:BH" + start);
var range2 = sheet.getRange(sortRange2);
let sortOrder2 = [
{column: 6, ascending: true},
{column: 11, ascending: true},
{column: 4, ascending: true}
];
range2.sort(sortOrder2);
}
再次非常感谢@Boris Baublys