C++ cout 打印二维字符数组的全部内容

C++ cout prints entire contents of 2D char array

我正在写一个井字游戏来学习C++。

我想将游戏板存储在二维字符数组中:

    char playerBoard[5][14] {
        {'2',' ','>',' ','_',' ','|',' ','_',' ','|',' ','_','\n'},
        {'1',' ','>',' ','_',' ','|',' ','_',' ','|',' ','_','\n'},
        {'0',' ','>',' ','_',' ','|',' ','_',' ','|',' ','_','\n'},
        {' ',' ',' ',' ','^',' ',' ',' ','^',' ',' ',' ','^','\n'},
        {' ',' ',' ',' ','0',' ',' ',' ','1',' ',' ',' ','2','\n'}
    };

我想用 cout 打印数组:

    for (int i = 0; i < 5; i++) {
            cout << playerBoard[i];
        }

当我尝试时,从第一个数组开始,每次迭代都会打印 playerboard 的全部内容:


    2 > _ | _ | _
    1 > _ | _ | _
    0 > _ | _ | _
        ^   ^   ^
        0   1   2
    1 > _ | _ | _
    0 > _ | _ | _
        ^   ^   ^
        0   1   2
    0 > _ | _ | _
        ^   ^   ^
        0   1   2
        ^   ^   ^
        0   1   2
        0   1   2

playerBoard 的全部内容打印为:

    cout << playerBoard[0];

这是怎么回事?

None 的五个数组子元素是一个以 nul 结尾的字符串(可能最后一个除外,但它依赖于未定义的行为)。

带有 char* 操作数(或 char[] 操作数,decays into a char*)的 std::cout << 操作假定一个以 nul 结尾的字符串;在您的情况下,由于缺少终止符,因此会打印缓冲区,直到在某处找到一个为止。这似乎是在整个数组块之后。

要解决此问题,请将子数组的大小增加到 15 个字符并添加所需的 nul(零)终止符:

int main()
{
    char playerBoard[5][15]{
        {'2',' ','>',' ','_',' ','|',' ','_',' ','|',' ','_','\n','[=10=]'},
        {'1',' ','>',' ','_',' ','|',' ','_',' ','|',' ','_','\n','[=10=]'},
        {'0',' ','>',' ','_',' ','|',' ','_',' ','|',' ','_','\n','[=10=]'},
        {' ',' ',' ',' ','^',' ',' ',' ','^',' ',' ',' ','^','\n','[=10=]'},
        {' ',' ',' ',' ','0',' ',' ',' ','1',' ',' ',' ','2','\n','[=10=]'}
    };
    for (int i = 0; i < 5; i++) {
        std::cout << playerBoard[i];
    }
    return 0;
}

你有未定义的行为,因为 std::cout << playerBoard[i]; 期望 playerBoard[i] 是(指向第一个元素的指针)一个空终止数组,并且没有空字符(char{0} ).

要解决此问题,请使用适用于非空终止字符数组的 std::cout.write(s, count) or std::string_view

for (int i = 0; i < 5; i++) {
    std::cout.write(playerBoard[i], std::size(playerBoard[i]));
    // Or
    std::cout << std::string_view(playerBoard[i], std::size(playerBoard[i]));
}

或者,在末尾添加一个空终止符:

char playerBoard[][14] {
    {'2',' ','>',' ','_',' ','|',' ','_',' ','|',' ','_','\n'},
    {'1',' ','>',' ','_',' ','|',' ','_',' ','|',' ','_','\n'},
    {'0',' ','>',' ','_',' ','|',' ','_',' ','|',' ','_','\n'},
    {' ',' ',' ',' ','^',' ',' ',' ','^',' ',' ',' ','^','\n'},
    {' ',' ',' ',' ','0',' ',' ',' ','1',' ',' ',' ','2','\n'},
    {0}
};

// Print the whole array
std::cout << *playerBoard;

// (You can still print individual lines the same way like as above)