使用擦除删除 class 对象数组中的元素
Using erase for removing an element in an array of class objects
我想删除给定卷号的特定学生对象。从学生列表中使用 STL 中的擦除操作。以下是我的 class 设计。
但是编译器在我使用擦除函数的地方显示了以下错误信息。
no instance of overloaded function "std::vector<_Tp, _Alloc>::erase [with _Tp=Student, _Alloc=std::allocator<Student>]" matches the argument list -- argument types are: (Student) -- object type is: std::vector<Student, std::allocator<Student>>
#include <iostream>
#include <vector>
#include <cstring>
#include <algorithm>
using namespace std;
class Student
{
int roll;
char *name;
int score;
public:
Student(int r=0)
{
roll=r;
}
void get_data()
{
cout<<"Enter roll : ";
cin>>roll;
cout<<"Enter name : ";
cin>>name;
cout<<"Score : ";
cin>>score;
}
void show_data()
{
cout<<"Roll : "<<roll<<endl;
cout<<"Name : "<<name<<endl;
cout<<"Score : "<<score<<endl;
}
int ret_score()
{
return score;
}
int ret_roll()
{
return roll;
}
};
class Student_array
{
public:
vector <Student> Student_array;
vector <Student>::iterator it;
void add_student()
{
Student s;
s.get_data();
Student_array.push_back(s);
}
void remove_student()
{
int roll;
cout<<"Enter roll no. of the student to be removed : ";
cin>>roll;
for(int i=0;i<Student_array.size();i++)
{
if(roll==Student_array[i].ret_roll())
{
Student_array.erase(Student_array[i]);
break;
}
}
cout<<"Roll no. not found enter a valid roll no.\n";
}
};
std::vector::erase()
将迭代器作为输入,而不是 Student
对象,例如:
void remove_student()
{
int roll;
cout << "Enter roll no. of the student to be removed : ";
cin >> roll;
for(int i = 0; i < Student_array.size(); ++i)
{
if (roll == Student_array[i].ret_roll())
{
Student_array.erase(Student_array.begin() + i);
return; // <-- not 'break'!
}
}
cout << "Roll no. not found enter a valid roll no.\n";
}
或者,您可以使用 std::find_if()
来查找所需的 Student
而不是使用手动循环,例如:
void remove_student()
{
int roll;
cout << "Enter roll no. of the student to be removed : ";
cin >> roll;
auto iter = std::find_if(Student_array.begin(), Student_array.end(),
[=](Student &s){ return s.ret_roll() == roll; }
);
if (iter != Student_array.end())
Student_array.erase(iter);
else
cout << "Roll no. not found enter a valid roll no.\n";
}
你必须使用迭代器来擦除一个元素
for (auto iter = Student_array.begin(); iter != Student_array.end(); ++iter)
{
if (roll != iter->ret_roll())
continue;
Student_array.erase(iter);
break;
}
我想删除给定卷号的特定学生对象。从学生列表中使用 STL 中的擦除操作。以下是我的 class 设计。 但是编译器在我使用擦除函数的地方显示了以下错误信息。
no instance of overloaded function "std::vector<_Tp, _Alloc>::erase [with _Tp=Student, _Alloc=std::allocator<Student>]" matches the argument list -- argument types are: (Student) -- object type is: std::vector<Student, std::allocator<Student>>
#include <iostream>
#include <vector>
#include <cstring>
#include <algorithm>
using namespace std;
class Student
{
int roll;
char *name;
int score;
public:
Student(int r=0)
{
roll=r;
}
void get_data()
{
cout<<"Enter roll : ";
cin>>roll;
cout<<"Enter name : ";
cin>>name;
cout<<"Score : ";
cin>>score;
}
void show_data()
{
cout<<"Roll : "<<roll<<endl;
cout<<"Name : "<<name<<endl;
cout<<"Score : "<<score<<endl;
}
int ret_score()
{
return score;
}
int ret_roll()
{
return roll;
}
};
class Student_array
{
public:
vector <Student> Student_array;
vector <Student>::iterator it;
void add_student()
{
Student s;
s.get_data();
Student_array.push_back(s);
}
void remove_student()
{
int roll;
cout<<"Enter roll no. of the student to be removed : ";
cin>>roll;
for(int i=0;i<Student_array.size();i++)
{
if(roll==Student_array[i].ret_roll())
{
Student_array.erase(Student_array[i]);
break;
}
}
cout<<"Roll no. not found enter a valid roll no.\n";
}
};
std::vector::erase()
将迭代器作为输入,而不是 Student
对象,例如:
void remove_student()
{
int roll;
cout << "Enter roll no. of the student to be removed : ";
cin >> roll;
for(int i = 0; i < Student_array.size(); ++i)
{
if (roll == Student_array[i].ret_roll())
{
Student_array.erase(Student_array.begin() + i);
return; // <-- not 'break'!
}
}
cout << "Roll no. not found enter a valid roll no.\n";
}
或者,您可以使用 std::find_if()
来查找所需的 Student
而不是使用手动循环,例如:
void remove_student()
{
int roll;
cout << "Enter roll no. of the student to be removed : ";
cin >> roll;
auto iter = std::find_if(Student_array.begin(), Student_array.end(),
[=](Student &s){ return s.ret_roll() == roll; }
);
if (iter != Student_array.end())
Student_array.erase(iter);
else
cout << "Roll no. not found enter a valid roll no.\n";
}
你必须使用迭代器来擦除一个元素
for (auto iter = Student_array.begin(); iter != Student_array.end(); ++iter)
{
if (roll != iter->ret_roll())
continue;
Student_array.erase(iter);
break;
}