如何修改java中的HttpServletRequest body？

Question

我想在请求正文到达 Http Servlet 并获取 processed.The JSON 请求正文的有效负载之前修改它，我想摆脱“PayamtChqmanViewObject "（细节）部分。

{
      "ChqAccCode": "1",
      "ChqAmt": 1,
      "ChqBankCompCode": "TEST",
      "ChqBchName": "TEST",
      "ChqBchPost": "Y",
      "ChqPostDate":"2020-08-14",
      "ChqCompCode": "TEST",
      "ChqDate": "2020-04-21",
      "ChqDeptCode": "0",
      "ChqDesc": "TEST",
      "ChqDraftCode": "M",
      "ChqJobCode": null,
      "ChqJointVenName": null,
      "ChqNum": 123,
      "ChqPayeeAddr1": "Rome",
      "ChqPayeeAddr2": "1",
      "ChqPayeeAddr3": "Rome",
      "ChqPayeeCountry": "Italy",
      "ChqPayeeName1": "A1",
      "ChqPayeeName2": null,
      "ChqPayeePostalCode": "85695",
      "ChqPayeeRegCode": "IT",
      "ChqRecCode": "O",
      "ChqSeqNum": "1",
      "ChqVenCode": "ZZ",
      "ChqVouCode": null,
      "PayamtChqmanViewObj":[
        {
          "PaCompCode": "ZZ",
          "PaChqCompCode": "ZZ",
          "PaVenCode": "ACME",
          "PaChqNum": 123,
          "PaPayCurrAmt": 1,
          "PaAmt": 1,
          "PaVouInvCode": "INV001",
          "PaDiscAmt": 0,
          "PaChqSeqNum": "1"
        }
   ]
}

我可以使用以下方法获取请求主体，但是我不确定如何删除 JSON 的详细信息部分并将处理后的请求主体传递给 HTTP Servlet。

 public static String getBody(HttpServletRequest request) throws IOException {

        String body = null;
        StringBuilder stringBuilder = new StringBuilder();
        BufferedReader bufferedReader = null;

        try {
            InputStream inputStream = request.getInputStream();
            if (inputStream != null) {
                bufferedReader = new BufferedReader(new InputStreamReader(inputStream));
                char[] charBuffer = new char[128];
                int bytesRead = -1;
                while ((bytesRead = bufferedReader.read(charBuffer)) > 0) {
                    stringBuilder.append(charBuffer, 0, bytesRead);
                }
            } else {
                stringBuilder.append("");
            }
        } catch (IOException ex) {
            throw ex;
        } finally {
            if (bufferedReader != null) {
                try {
                    bufferedReader.close();
                } catch (IOException ex) {
                    throw ex;
                }
            }
        }

        body = stringBuilder.toString();
        System.out.println("BODY IS:" + body);
        return body;
    }

非常感谢您的帮助！

Answer 1

您无法更改请求，但可以包装它。有关详细信息，请参阅以下问题：

您需要在您的 servlet 前面放置一个 servlet filter 以使包装工作。

至于如何从内容中删除该部分，您可以使用 String class 提供的普通旧字符串操作，或者使用 StringUtils, or you could parse the JSON 之类的方法您选择的库，删除属性，然后将其作为字符串写回。

如何修改java中的HttpServletRequest body？

How to modify HttpServletRequest body in java?

java

servlets

http

request

servlet-filters