如何将 sql 转换为查询生成器 laravel
how to convert sql to query builder laravel
谁能帮我把这个 SQL 转换成查询生成器!
SELECT topwords.*,
mw.word AS my_word
FROM topwords
LEFT JOIN (SELECT DISTINCT words.word
FROM definition_word
JOIN words
ON words.id = definition_word.word_id
WHERE definition_word.user_id = $user) AS mw
ON topwords.word = mw.word
我对如何在 leftjoin 中使用子查询有疑问!
我试过类似的方法,但它有错误!
See error as image
DB::table('topwords')
->leftJoin(DB::raw("SELECT DISTINCT
words.word
FROM definition_word
JOIN words ON words.id = definition_word.word_id
WHERE definition_word.user_id = $user as mw"),"topwords.word", "=", "mw.word" )
->select(
"topwords.*",
"mw.word AS my_word"
)->orderBy('id','desc')->paginate(15);
由于 paginate 和 aggregation
你有这个错误
尝试使用 LengthAwarePaginator 进行自定义分页
示例如下:Laracast
所以你需要做这样的事情:
$query = DB::table('topwords')
->leftJoin(DB::raw("SELECT DISTINCT
words.word
FROM definition_word
JOIN words ON words.id = definition_word.word_id
WHERE definition_word.user_id = $user as mw"),"topwords.word", "=", "mw.word" )
->select(
"topwords.*",
"mw.word AS my_word"
);
$paginator = new LengthAwarePaginator($query->get(), $query->count(), $request->input('per_page', 15), $request->input('page', 1));
然后就可以在collection
中使用了
可以使用Join Sub查询官方文档subquery-joins
$mw = DB::table('words')
->select('DISTINCT words.word')
->join('definition_word', function($join) use ($user)
{
$join->on('wordss.id', '=', 'definition_word.word_id')
->where('definition_word.user_id', $user);
});
$topwords = DB::table('topwords')
->joinSub($mw, 'mw',function ($join) {
$join->on('topwords.word', '=', 'mw.word');
})
->select('topwords.*','mw.word AS my_word')
->orderBy('id','desc')
->paginate(15);
谁能帮我把这个 SQL 转换成查询生成器!
SELECT topwords.*,
mw.word AS my_word
FROM topwords
LEFT JOIN (SELECT DISTINCT words.word
FROM definition_word
JOIN words
ON words.id = definition_word.word_id
WHERE definition_word.user_id = $user) AS mw
ON topwords.word = mw.word
我对如何在 leftjoin 中使用子查询有疑问!
我试过类似的方法,但它有错误! See error as image
DB::table('topwords')
->leftJoin(DB::raw("SELECT DISTINCT
words.word
FROM definition_word
JOIN words ON words.id = definition_word.word_id
WHERE definition_word.user_id = $user as mw"),"topwords.word", "=", "mw.word" )
->select(
"topwords.*",
"mw.word AS my_word"
)->orderBy('id','desc')->paginate(15);
由于 paginate 和 aggregation
你有这个错误尝试使用 LengthAwarePaginator 进行自定义分页
示例如下:Laracast
所以你需要做这样的事情:
$query = DB::table('topwords')
->leftJoin(DB::raw("SELECT DISTINCT
words.word
FROM definition_word
JOIN words ON words.id = definition_word.word_id
WHERE definition_word.user_id = $user as mw"),"topwords.word", "=", "mw.word" )
->select(
"topwords.*",
"mw.word AS my_word"
);
$paginator = new LengthAwarePaginator($query->get(), $query->count(), $request->input('per_page', 15), $request->input('page', 1));
然后就可以在collection
中使用了可以使用Join Sub查询官方文档subquery-joins
$mw = DB::table('words')
->select('DISTINCT words.word')
->join('definition_word', function($join) use ($user)
{
$join->on('wordss.id', '=', 'definition_word.word_id')
->where('definition_word.user_id', $user);
});
$topwords = DB::table('topwords')
->joinSub($mw, 'mw',function ($join) {
$join->on('topwords.word', '=', 'mw.word');
})
->select('topwords.*','mw.word AS my_word')
->orderBy('id','desc')
->paginate(15);